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seropon [69]
3 years ago
10

SIGNS. *

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
3 0

im not smart enough lol

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Two mechanics worked on a car. The first mechanic worked for 15
nevsk [136]

Answer: For the sum of 130

First: $90

Second: $40

Step-by-step explanation:

We write equations for each part of this situation.

<u>The Total Charge</u>

Together they charged 1550. This means 1550 is made up of the first mechanics rate for 15 hours and the second's rate for 5 hours. Lets call the first's rate a, so he charges 15a. The second's let's call b. He charges 5b. We add them together 15a+5b=1550.

<u>The Sum of the Rates</u>

Since the first's rate is a and the second is b, we can write a+b=130 since their sum is 130.

We solve for a and b by substituting one equation into another. Solve for the variable. Then substitute the value into the equation to find the other variable.

For a+b=130, rearrange to b=130-a and substitute into 15a+5b=1550.

15a + 5 (130-a)=1550

15a+650-5a=1550

10a+650-650=1550-650

10a=900

a=$90 was charged by the first mechanic.

We substitute to find the second mechanic's rate.

90+b=130

90-90+b=130-90

b= $40 was charged by the second mechanic

5 0
3 years ago
A man claims to have extrasensory perception (ESP). As a test, a fair coin is flipped 23 times, and the man is asked to predict
77julia77 [94]

The probability that he would have done at least this well if he had no ESP is 0.99979

<h3>What is the probability of determining that he would have done well with no ESP?</h3>

To determine the probability, we need to first find the probability of doing well with ESP.

The probability of having 20 correct answers out of 23 coin flips is:

\mathbf{=(\dfrac{1}{2})^{20}}

Since we have 20 correct answers, we also need to find the probability of getting 3 answers wrong, which is:

\mathbf{=(\dfrac{1}{2})^{3}}

There are (^{23}_{20}) = 1771 ways to get 20 correct answers out of 23.

Therefore, the probability of doing well with ESP is:

\mathbf{= 1771 \times (\dfrac{1}{2})^{20}} \times (\dfrac{1}{2})^{3}}

= 0.00021

The probability that he would have at least done well if he had no ESP is:

= 1 - 0.00021

= 0.99979

Learn more about probability here:

brainly.com/question/24756209

#SPJ1

8 0
2 years ago
PLEASE HELP
Novay_Z [31]
It would be C!!!!!!!!!!!!!!!
6 0
4 years ago
How many bags of cotton balls would it take to make (6) 10inch pillows out of 1yard of fabric?
IgorLugansk [536]

Answer:

you should know this. you tell me how many?

3 0
3 years ago
The value of the under lined digit of 6,035
dem82 [27]
Which number is the under lined digit?
7 0
4 years ago
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