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Alex787 [66]
3 years ago
8

A quadrilateral with no sides parallel and diagonals that are perpendicular

Mathematics
1 answer:
Drupady [299]3 years ago
5 0
<h3>Answer:  Quadrilateral</h3>

======================================================

Explanation:

Of your original given list, let's write down the parallelograms. They are:

  • Parallelogram
  • Rectangle
  • Rhombus
  • Square

So we cross those off the list since we want a quadrilateral with no sides parallel. A parallelogram, by definition, is a quadrilateral with both pairs of opposite sides that are parallel.

We can also rule out the trapezoids because a trapezoid is a four sided figure (quadrilateral) where we have exactly 1 pair of parallel sides, while the other sides are not parallel.

Lastly, we can rule out the kite because any kite has perpendicular diagonals.

The only thing left is quadrilateral. In my opinion this answer should be more specific and say "quadrilateral that isn't a parallelogram, a trapezoid, or a kite", but I think I see what your teacher was going for here.

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Answer:  b≥-3

Step-by-step explanation:

at least means that it's great or equal than -3.

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3 years ago
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Answer:

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Step-by-step explanation:

6x - 4 = 8

Add 4 to both sides.

6x = 12

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6x - 4 = 8

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Subtract 4 from 12.

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2 years ago
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7 0
3 years ago
Mr. Monasterio ran to the store for burritos at 4 miles per hour. On the way back, he increased his speed to 6 miles per hour. I
sveticcg [70]

Answer:

It took 1.2 hours to get to the store

Step-by-step explanation:

Let the time taken to reach the store be t₁

Let the time taken to come back be t₂

Let the speed to and from store = s₁ and s₂ respectively

let the distance to the store = d

To the store:

speed = \frac{distance}{time} \\s = \frac{d}{t_1} \\t_1 = \frac{d}{s_1}\\t_1 =\frac{d}{4} - - - - - (1)

Back from the store:

s_2 = \frac{d}{t_2} \\t_2 = \frac{d}{s_2}\\where:\\s_2 = 6\ miles\ per\ hour\\t_2 = \frac{d}{6} - - - - - - (2)

We are told that total time (t₁ + t₂) = 2 hours

t₁ + t₂ = eqn (1) + eqn (2)

\frac{d}{4} + \frac{d}{6} = 2\\Multiplying\ through\ by\ 12:\\3d\ +\ 2d\ =\ 24\\5d = 24\\d = \frac{24}{5} \\d = 4.8\ miles

∴ length of trip to the store = t₁

from eqn (1)

t_1 = \frac{d}{4} \\t_1 = \frac{4.8}{4} \\t_1 = 1.2\ hours

7 0
3 years ago
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