700/200=7/2 because devide by 100 and then=3 1/2 and half is .5 so=
3.5
We use letters to represent the unknown coins.
P for pennies that worth 1 cents
N for nickels that worth 5 cents
D for dimes that worth 10 cents
Q for quarters that worth 25 cents.
<span>"He has twice as many nickels (N) as dimes (D)" So D=2N
</span><span>"and four times as many pennies (P) as quarters (Q)." So Q=4P
</span>
Number of coins equals P+N+D+Q=P+N+2N+4P (Dimes and quarters are written in terms of nickels and pennies, respectively)
So, number of coins is equal to 5P+3N=201. Thats is the first equation (I)
To write the second equation, use cents of coins. 12.10 $ in coins can be shown as
5P. 1 cent + 3N. 5 cent=1210 cents or simply 5P + 15N=1210 (Second equation)
We have two equations and two unknowns so it is soluble.
number of coins: 5P+3N=201 (I)
cents of coins: 5P+15N=1210 (II)
Use the substitution method. (II) - (I)=12N=1009
N=1009/12=84 ( Actually it is 84.08)
D=2N=168
P= -10
Q=-40
Number of pennies and quarters are <span>meaningless. They can't be negative. So they should be something wrong in the question.</span>
9514 1404 393
Answer:
121/14 or 8 9/14
Step-by-step explanation:
The quotient of 1/8 and 1/4 is ...
(1/8)/(1/4) = (1/8)(4/1) = 4/8 = 1/2
The product of 2 2/3 and 3 3/7 is ...
(2 2/3)(3 3/7) = (8/3)(24/7) = (8·24)/(3·7) = 64/7
Subtracting the first result from the second gives ...
64/7 -1/2 = (128 -7)/14 = 121/14 = 8 9/14
_____
<em>Additional comment</em>
When subtracting fractions with denominators that have no common factors, I find it useful to make use of the formula ...
![\dfrac{a}{b}-\dfrac{c}{d}=\dfrac{ad-bc}{bd}](https://tex.z-dn.net/?f=%5Cdfrac%7Ba%7D%7Bb%7D-%5Cdfrac%7Bc%7D%7Bd%7D%3D%5Cdfrac%7Bad-bc%7D%7Bbd%7D)
In this case, that gives us (64·2 -7·1)/(7·2) = (128 -7)/14.
1. The set of stairs is not safe.
3.6 / 4 = 0.9
0.9 > 0.87
2. see photo below