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3 years ago

4. ADEF is an equilateral triangle. E 24 20 D F

Mathematics

1 answer:

irinina [24]3 years ago

7 0

By Pythagorean theorem

x²+GF²=EF² ( where G is the point of intersection of perpendicular lines)

now, GF=1/2 EF= 12

x²+12²=24²

x²=24²-12²

x²=432

x=√432

x=12√3

x≈20.78

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I NEED HELP PLEASE, THANKS! :)

ICE Princess25 [194]

Answer: G ∩ M = {Anael, Max}

G U S = {Acel, Acton, Anael, Barek, Carl, Carlin, Dario, Kai, Max}

Step-by-step explanation:

intersection ∩ - items found in BOTH sets

union U - the joining of the sets. include EVERYTHING in the sets.

G = (Acel, Acton, Anael, Carl, Dario, Max}

S = {Anael, Barek, Bay, Carlin, Kai, Max}

G ∩ S: Anael and Max are found in both sets

G = (Acel, Acton, Anael, Carl, Dario, Max}

S = {Acton, Anael, Barek, Carlin, Dario, Kai}

G U S: include everything in G and everything in S. If found in both sets, only list it once.

G U S = {Acel, Acton, Anael, Barek, Carl, Carlin, Dario, Kai, Max}

Notice that Acton and Anael are in both sets but we only list them once.

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3 years ago

Solve 16x+9=9y−2x16x+9=9y−2x for y

denis23 [38]

16x + 9 = 9y-2x Add 2x to both sides
18x + 9 = 9y Divide both sides by 9
2x + 1 = y Switch the sides to make it easier to read
y = 2x + 1

6 0

3 years ago

The given matrix is the augmented matrix for a linear system. Use technology to perform the row operations needed to transform t

shtirl [24]

Answer:

$x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\$

Step-by-step explanation:

As the given Augmented matrix is

$\left[\begin{array}{ccccc}9&-2&0&-4&:8\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]$

Step 1 :

$r_{1}$ ↔ $r_{1} - r_{2}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]$

Step 2 :

$r_{3}$ ↔ $r_{3} - 8r_{1}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\0&124&-54&77&:-82\end{array}\right]$

Step 3 :

$r_{2}$ ↔ $\frac{r_{2}}{7}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&124&-54&77&:-82\end{array}\right]$

Step 4 :

$r_{1}$ ↔ $r_{1} + 14r_{2}$ , $r_{3}$ ↔ $r_{3} - 124r_{2}$

$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&- \frac{254}{7} &\frac{663}{7} &:-\frac{1690}{7} \end{array}\right]$

Step 5 :

$r_{3}$ ↔ $\frac{r_{3}. 7}{254}$

$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&1&-\frac{663}{254} &:-\frac{1690}{254} \end{array}\right]$

Step 6 :

$r_{1}$ ↔ $r_{1} - 4r_{3}$ , $r_{2}$ ↔ $r_{2} + \frac{1}{7} r_{3}$

$\left[\begin{array}{ccccc}1&0&0&-\frac{71}{127} &:\frac{176}{127} \\0&1&0&-\frac{131}{254} &:\frac{284}{127} \\0&0&1&-\frac{663}{254} &:\frac{845}{127} \end{array}\right]$

∴ we get

$x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\$

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3 years ago

What is the Value of “X” Type answer -

NARA [144]

Answer: 96º

Step-by-step explanation:

the added angles of a triangle will be 180º

brainliest if its right?

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3 years ago

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