Answer: Context
I get how Nikolai is working at home and will be getting paid $20 but despite the $25 being at a factory and is repetitive, here is a little word from experience. The $25 is a start-off which is pretty good and it won't always be at a factory. If Nikolai is working hard and repetitive, he will be promoted to the fact where he will be paid more and work at home time-to-time. The $20 one, however, is a work-at-home type and since there is children, the house will have to be quiet during calls and what-not.
Amy: x skirts
Betty: 2x skirts
Carol: (2x) + 7 skirts
If Amy has 18 less than Carol, than Carol's equation minus 18 equals Amy's equation:
[(2x) + 7] - 18 = x
+18 +18
(2x) + 7 = x + 18
- 7 -7
2x = x + 11
-x -x
x = 11
Input the solution for x into the girls equation to double check.
Amy: 11
Betty: 2(x)
2(11)
=22
Carol: (2x) + 7
22 + 7
=29
Does Amy have 18 less than Carol?
Carol - Amy = 18
29 - 11 = 18
18 = 18
the problem is solved
B = block p = park
2b + p = 10 min 2 runs around the block takes 10 minutes
2b + 3p = 22 min 2 runs around the block plus 3 runs around the park takes 22 minutes
To solve, I will use substitution. First, I will divide the first equation by 2 to get b by itself and subtract p from both sides to get b by itself. Then, substitute 5 - 1/2p in for b in the second equation because they have equal values. Then, subtract 10 from both sides to eliminate it. Divide by 2 to both sides to get 'p' by itself.
2b + p = 10 min ---------→b + 1/2p = 5 ----------→ b = 5 - 1/2p
2(5 - 1/2p) + 3p = 22 ---------→ 10 -p + 3p = 22 --------→ 10 + 2p = 22
10 + 3p = 22 ----------→ 2p = 12
2p = 12 -------------→ p = 6
It takes 6 minutes to jog around the park
Hope this helps!
I think the answer might be 52 degrees! Good luck
A. Yes you are correct that the gradient at any point is 3/(3x-1). However at point P it would be 3/(3*2-1)=2/5
b. The gradient of the normal would therefore be -5/2
We can use the general formula of an equation to get y-ln(5)=-5/2 (x-2)
Now multiply both sides by 2 to get:
2y-2ln(5)=-5x+10
Now when it crosses the x axis we know that y=0 therefore:
5x=10+2ln(5)
Therefore:
x=2+2/5 ln(5) when y=0
You could find an estimate of this number to be 2.64 (3sf) but this might not be sufficient
