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3 years ago

A pool is surrounded by a rectangular fence with a

Mathematics

1 answer:

PtichkaEL [24]3 years ago

7 0

Answer:

width is 33

Step-by-step explanation:

width (b) =?

length(l)=3

perimeter (p)=?

now,

perimeter = 2(l+b)

or,72= 2(3+ b)

or,72/2= 3+b

or,36= 3+b

or,36-3= b

or,33= b

therefore width is 33

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never [62]

Answer:

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3 years ago

Given that a:b:c= 20 : 35 : 15, a) simplify a : b:c, b) find a:b,

Furkat [3]

Answer:

a) 4:7:3

b) 4:7 / 20:35

c) 3:7 / 15:35

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2 years ago

I need help on C, D, E, F, G, and H. The mean is 27, and the Standard Deviation is 15.01

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3 years ago

David and Lacey are 2000 feet apart on a coastline. They each look at the same boat in the water. The angle between the coastlin

Ulleksa [173]

By using the given distances and directions, we have;

Part A: 1083.5 feet

Part B: 1921.37 feet

Part C: 58.05°

<h3>How can the distances and directions be calculated?</h3>

The distance between David and Lacey = 2000 feet

David's angle to the boat = 70°

Lacey's angle to the boat = 32°

Part A

The distance of the boat from David is found as follows;

Imaginary lines drawn from the boat to David and then to Lacey form a triangle.

In the triangle, let A = 70°

B = 32°

Therefore by the sum of angles in a triangle, we have;

C = 180° - (70° + 32°) = 78°

By using sine rule we have;

$\frac{a}{sin(A)} = \frac{b}{sin( B )} = \frac{c}{sin(C)}$

David's distance from the boat, b, is therefore;

$\frac{b}{sin( 32 )} = \frac{2000}{sin(78)}$

The angle subtended by the coastline, C, is therefore;

$b = \frac{2000}{sin(78)} \times sin( 32 ) = 1083.5$

David's distance from the boat is 1083.5 feet

Part B

The distance between the boat and Lacey is found as follows;

$\mathbf{ \frac{a}{sin( 70)} }= \frac{2000}{sin(78)}$

$a = \frac{2000}{sin(78)} \times sin( 70 ) = 1921.37$

Lacey's distance from the boat is 1921.37 feet

Part C

When b = 1200 feet, we have;

Finding the vertical distance of the boat from the coastline, we have;

1083.5 × sin(70) = 1018.17

We have;

$\frac{1200}{sin(90)} = \frac{1018.17}{sin( B' )}$

${sin( B' )} = \frac{sin(90)}{1200} \times 1018.17$

The angle between the coastline and his view to the boat, B', is therefore;

B' = arcsine (1018.17÷1200) = 58.05°

Learn more about sine rule here:

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4 0

2 years ago

X3−3=x9+3 what the answer

dlinn [17]

x = x ≈ − 1.25992104

3 0

3 years ago