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bearhunter [10]
3 years ago
8

Please help!!! will give brainliest

Mathematics
2 answers:
mina [271]3 years ago
8 0

Answer:

The answer is B

Step-by-step explanation:

3 to the forth power = 81

3 to the second power = 9

81/9 = 9

evablogger [386]3 years ago
5 0

Answer:

b: 9

Step-by-step explanation:

3x3x3x3= 81

3x3=9

81/9=9

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lamont cotton is 4% comission on the first 10,000 of monthly sales mens 10% on all sales over 10,000. last month his 38,00. what
Pani-rosa [81]

Given:

Lamont cotton is 4% commission on the first 10,000 of monthly sales and 10% on all sales over 10,000.

Consider his last month sales is 38,000.

To find:

The total commission.

Solution:

4% commission on the first 10,000 of monthly sales is

10,000\dfrac{4}{100}=400

Sales over 10,000 is

38,000-10,000=28,000

10% commission on all sales over 10,000 is

28,000\times \dfrac{10}{100}=2,800

Now, the total commission is

400+2,800=3,200

Therefore, the total commission is 3,200.

8 0
2 years ago
How to find the slope
nirvana33 [79]

Answer:

m= \frac{y_2-y_1}{x_2-x_1}

Step-by-step explanation:

use this formula if you're having two points or a graph

6 0
2 years ago
A box contains 10 red ribbons and 12 blue ribbons. Once a ribbon is picked, it is not replaced. What is the probability of choos
lora16 [44]
I belive the answer is 1.
This is because out of 22 ribbon there are 10 which are bue so the probability of blue ribbons is 10/22 and probability of red ribbon is 12/22. So your question was the probability of choosing a red ribbon then a blu ribbon. Because of the word "then" , this means it is simply asking you to add their probablity so after adding 10/22 with 12/22 your answer will come to 22/22 which is equal to 1.
3 0
3 years ago
What is the area of the original rectangle?
saw5 [17]

It is 8

As a result of multiply 1.6 times 6, we would also need to apply it to the side as well, and therefore multiply it.

8 0
3 years ago
Read 2 more answers
1. Express <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bx%282x%2B3%29%20%7D" id="TexFormula1" title="\frac{1}{x(2x+3) }" a
katovenus [111]

1. Let a and b be coefficients such that

\dfrac1{x(2x+3)} = \dfrac ax + \dfrac b{2x+3}

Combining the fractions on the right gives

\dfrac1{x(2x+3)} = \dfrac{a(2x+3) + bx}{x(2x+3)}

\implies 1 = (2a+b)x + 3a

\implies \begin{cases}3a=1 \\ 2a+b=0\end{cases} \implies a=\dfrac13, b = -\dfrac23

so that

\dfrac1{x(2x+3)} = \boxed{\dfrac13 \left(\dfrac1x - \dfrac2{2x+3}\right)}

2. a. The given ODE is separable as

x(2x+3) \dfrac{dy}dx} = y \implies \dfrac{dy}y = \dfrac{dx}{x(2x+3)}

Using the result of part (1), integrating both sides gives

\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3|\right) + C

Given that y = 1 when x = 1, we find

\ln|1| = \dfrac13 \left(\ln|1| - \ln|5|\right) + C \implies C = \dfrac13\ln(5)

so the particular solution to the ODE is

\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3|\right) + \dfrac13\ln(5)

We can solve this explicitly for y :

\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3| + \ln(5)\right)

\ln|y| = \dfrac13 \ln\left|\dfrac{5x}{2x+3}\right|

\ln|y| = \ln\left|\sqrt[3]{\dfrac{5x}{2x+3}}\right|

\boxed{y = \sqrt[3]{\dfrac{5x}{2x+3}}}

2. b. When x = 9, we get

y = \sqrt[3]{\dfrac{45}{21}} = \sqrt[3]{\dfrac{15}7} \approx \boxed{1.29}

8 0
2 years ago
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