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bearhunter [10]
2 years ago
8

Please help!!! will give brainliest

Mathematics
2 answers:
mina [271]2 years ago
8 0

Answer:

The answer is B

Step-by-step explanation:

3 to the forth power = 81

3 to the second power = 9

81/9 = 9

evablogger [386]2 years ago
5 0

Answer:

b: 9

Step-by-step explanation:

3x3x3x3= 81

3x3=9

81/9=9

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If h()=² and () =h() +, what is the value of ?
bulgar [2K]

Answer:

negative six..........

7 0
3 years ago
Please help, will give brainliest!<br>(please explain how as well)​
vovikov84 [41]

Answer:

C

Step-by-step explanation:

Since GJ bisects ∠ FGH , then ∠ FGJ = ∠ JGH = x + 14

∠ FGH = ∠ FGJ + ∠ JGH , substitute values

4x + 16 = x + 14 + x + 14 = 2x + 28 ( subtract 2x from both sides )

2x + 16 = 28 ( subtract 16 from both sides )

2x = 12 ( divide both sides by 2 )

x = 6

Thus

∠ FGJ = x + 14 = 6 + 14 = 20° → C

4 0
2 years ago
Please HELP <br>what is the slope-intercept equation slope: -2 y-intercept: 3​
pshichka [43]

Answer:

y=-2x+3

Step-by-step explanation:

In a y=mx+b equation, M is the slope and B is the y intercept. So write down that equation and plug in the numbers you're given

5 0
2 years ago
Barbra can walk 3200 meters in 24 minutes. How far can she walk in 3 minutes show your work
vichka [17]
\frac{3200}{24}=\frac{n}{3}\\\frac{3200}{24}/\frac{8}{8}=\frac{n}{3}\\\frac{400}{3}=\frac{n}{3}\\\frac{400}{3}*3=\frac{n}{3}*3\\400=n\

400 meters
3 0
3 years ago
Find the exact length of the curve. 36y2 = (x2 − 4)3, 5 ≤ x ≤ 9, y ≥ 0
IrinaK [193]
We are looking for the length of a curve, also known as the arc length. Before we get to the formula for arc length, it would help if we re-wrote the equation in y = form.

We are given: 36 y^{2} =( x^{2} -4)^3
We divide by 36 and take the root of both sides to obtain: y = \sqrt{ \frac{( x^{2} -4)^3}{36} }

Note that the square root can be written as an exponent of 1/2 and so we can further simplify the above to obtain: y =  \frac{( x^{2} -4)^{3/2}}{6} }=( \frac{1}{6} )(x^{2} -4)^{3/2}}

Let's leave that for the moment and look at the formula for arc length. The formula is L= \int\limits^c_d {ds} where ds is defined differently for equations in rectangular form (which is what we have), polar form or parametric form.

Rectangular form is an equation using x and y where one variable is defined in terms of the other. We have y in terms of x. For this, we define ds as follows: ds= \sqrt{1+( \frac{dy}{dx})^2 } dx

As a note for a function x in terms of y simply switch each dx in the above to dy and vice versa.

As you can see from the formula we need to find dy/dx and square it. Let's do that now.

We can use the chain rule: bring down the 3/2, keep the parenthesis, raise it to the 3/2 - 1 and then take the derivative of what's inside (here x^2-4). More formally, we can let u=x^{2} -4 and then consider the derivative of u^{3/2}du. Either way, we obtain,

\frac{dy}{dx}=( \frac{1}{6})( x^{2} -4)^{1/2}(2x)=( \frac{x}{2})( x^{2} -4)^{1/2}

Looking at the formula for ds you see that dy/dx is squared so let's square the dy/dx we just found.
( \frac{dy}{dx}^2)=( \frac{x^2}{4})( x^{2} -4)= \frac{x^4-4 x^{2} }{4}

This means that in our case:
ds= \sqrt{1+\frac{x^4-4 x^{2} }{4}} dx
ds= \sqrt{\frac{4}{4}+\frac{x^4-4 x^{2} }{4}} dx
ds= \sqrt{\frac{x^4-4 x^{2}+4 }{4}} dx
ds= \sqrt{\frac{( x^{2} -2)^2 }{4}} dx
ds=  \frac{x^2-2}{2}dx =( \frac{1}{2} x^{2} -1)dx

Recall, the formula for arc length: L= \int\limits^c_d {ds}
Here, the limits of integration are given by 5 and 9 from the initial problem (the values of x over which we are computing the length of the curve). Putting it all together we have:

L= \int\limits^9_5 { \frac{1}{2} x^{2} -1 } \, dx = (\frac{1}{2}) ( \frac{x^3}{3}) -x evaluated from 9 to 5 (I cannot seem to get the notation here but usually it is a straight line with the 9 up top and the 5 on the bottom -- just like the integral with the 9 and 5 but a straight line instead). This means we plug 9 into the expression and from that subtract what we get when we plug 5 into the expression.

That is, [(\frac{1}{2}) ( \frac{9^3}{3}) -9]-([(\frac{1}{2}) ( \frac{5^3}{3}) -5]=( \frac{9^3}{6}-9)-( \frac{5^3}{6}-5})=\frac{290}{3}


8 0
3 years ago
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