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zheka24 [161]
3 years ago
10

Emplea los signos <, > o =, según corresponda​

Mathematics
1 answer:
katovenus [111]3 years ago
6 0

Answer:

1.≤

2.≤

3.≤

4.≤

5.≤

6.≤

Step-by-step explanation:

di po ko sure kung tama po yan

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Find the missing side
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Answer:

\huge\boxed{\sf x = 8.2}

Step-by-step explanation:

Since it is a right-angled triangle, we will apply Pythagoras Theorem.

<u>Given are:</u>

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Perpendicular = x

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<u>Pythagoras Theorem:</u>

\sf (Hypotenuse)^2=(Base)^2+(Perpendicular)^2

(18)² = (16)² + (x)²

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Subtract 256 to both sides

324 - 256 = x²

68 = x²

Take sqrt on both sides

8.2 = x

x = 8.2

\rule[225]{225}{2}

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2 years ago
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Answer:

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Step-by-step explanation:

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Someone please help me with number 6. Also show your work as that will help a lot
adoni [48]

\bf f(x) = x^2+3x+9 \\\\[-0.35em] ~\dotfill\\\\ \cfrac{(x+h)^2+3(x+h)+9~~~~-~~~~(x^2+3x+9)}{h} \\\\\\ \cfrac{(x+h)^2+3(x+h)+9~~~~~~-x^2-3x-9}{h} \\\\\\ \cfrac{\stackrel{F~~O~~I~~L}{(x^2+2hx+h^2)}+3x+3h+9~~~~~~-x^2-3x-9}{h}

\bf \cfrac{(2hx+h^2+3h)~~\begin{matrix} +x^2-x^2+3x-3x+9-9 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{h}\implies \cfrac{\stackrel{\textit{common factor}}{~~\begin{matrix} h \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~(2x+h+3)}}{~~\begin{matrix} h \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill 2x+h+3~\hfill

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