Speed = Distance ÷ Time
Distance = 2797.2
Time = 0.15
2797.2 / 0.15 = 18,648
Speed = 18,648
Answer: Second Option
(Point in Quadrant I)
Step-by-step explanation:
The solution to a system of linear equations is the point where the two lines intersect.
Note that in this case we have two lines with different slope . By definition, if two lines have different slopes and are contained in the same plane, then there will always be an intersection between them at some point in the plane.
Looking at the image, you can see that the lines get closer as x and y increase. Then they will intercept in the first quadrant.
i think this is the answer for n=-2/a+4
First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now
2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4
At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real.
Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result.
For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196
No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.
So x^2 = -4 has no real solutions. Taking the square root of both sides leads to
x^2 = -4
sqrt(x^2) = sqrt(-4)
|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
x = 2i or x = -2i
which are complex non-real values
Answer:
b.
( -3, -5)
Step-by-step explanation:
6x + 13 = 2x + 1
6x -2x = 1-13
4x = -12
x = -12/4 = -3
y = 6x + 13
y = 6(-3) +13 = -18+13 = -5
(x, y) = (-3,-5)
