How many centimeters long is a leg of an isosceles right triangle if its hypotenuse has a length of 8√2 centimeters?

Mathematics

1 answer:

andrew-mc [135]3 years ago

7 0

Answer:

The leg is 8 cm long

Step-by-step explanation:

An isosceles right triangle has the length of its hypotenuse and opposite equal

Let us call the length x

From Pythagoras’ , the square of the hypotenuse equals the sum of the squares of the two other sides

Thus, we have ;

x^2 + x^2 = (8 √2)^2

2x^2 = 128

x^2 = 128/2

x^2 = 64

x= √64

x = 8 cm

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Given: cosθ= -4/5 , sin x = -12/13 , θ is in the third quadrant, and x is in the fourth quadrant; evaluate tan 1/2 θ

mrs_skeptik [129]

Answer:

Step-by-step explanation:

If you're looking for what the half angle of the tangent of theta is, I'm a bit confused as to why you think the angle in the 4th quadrant, x, is relevant. But maybe you don't know it isn't and it's a "trick" to throw you off. Hmm...

Anyways, the half angle identity for tangent is

$tan(\frac{\theta}{2})=\frac{sin\theta}{1+cos\theta}$

There are actually 3 identities for the tangent of a half angle, but this one works just as well as either of the others do, so I'm going with this one.

If theta is in QIII, the value of -4 goes along the x axis and the hypotenuse is 5. That makes the missing side, by Pythagorean's Theorem, -3. Filling in our formula:

$tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{1+(-\frac{4}{5}) }$ which simplifies a bit to