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Snowcat [4.5K]
2 years ago
5

-4x < 28does anyone know the solution and answer?​

Mathematics
1 answer:
ratelena [41]2 years ago
6 0

Answer:

x>−7

Explanation:

Let's solve your inequality step-by-step.

−4x<28

Step 1: Divide both sides by -4.

−4x/−4 < 28/−4

x>−7

Answer: x>−7

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- Brainliest- friend me.A spinner is divided into four equal sections. Which situation can be represented using this simulation?
Verdich [7]

Answer:

im pretty sure its 2 answers

both a and c

hope this helps!!

5 0
3 years ago
Question below answer correctly please
ratelena [41]

Answer:

C: x≥12

D: x<-15

E: x<7.5 or 15/2

F: x<-8

G: x≥-2.7 or -8/3

H: x≥-6

Step-by-step explanation:

I trust you know how to graph it

3 0
2 years ago
Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 139 millimeters,
FinnZ [79.3K]

Answer:

0.4010 = 40.10% probability that the sample mean would differ from the population mean by more than 0.8 millimeters

Step-by-step explanation:

To solve this question, we need to understan the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 139, \sigma = 6, n = 40, s = \frac{6}{\sqrt{40}} = 0.9487

Either the sample mean differs by 0.8 mm or less from the population mean, or it differs by more. The sum of these probabilities is decimal 1.

Probability it differs by less than 0.8mm

pvalue of Z when X = 139 + 0.8 = 139.8mm subtracted by the pvalue of Z when X = 139 - 0.8 = 138.2 mm

X = 139.8

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{139.8 - 139}{0.9487}

Z = 0.84

Z = 0.84 has a pvalue of 0.7995

X = 138.2

Z = \frac{X - \mu}{s}

Z = \frac{138.2 - 139}{0.9487}

Z = -0.84

Z = -0.84 has a pvalue of 0.2005

0.7995 - 0.2005 = 0.5990

What is the probability that the sample mean would differ from the population mean by more than 0.8 millimeters?

p + 0.5990 = 0.4010

0.4010 = 40.10% probability that the sample mean would differ from the population mean by more than 0.8 millimeters

7 0
3 years ago
Drake buys a ring that costs $8,000, which depreciates at a rate of 9.5% per year.
Alex73 [517]

Answer:

$1129.93

Step-by-step explanation:

100 - 9.5 = 90.5

8000 - 90.5 = 7909.5

7909.5 ÷ 7 = 1129.93

i hope this helps

4 0
2 years ago
HELP ME PLEASE!!!<br> Find the area of the triangle shown below.
Jlenok [28]

Answer:

Sorry I don't know

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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