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defon
2 years ago
12

What is 2+21*13-45+12*67

Mathematics
2 answers:
Yanka [14]2 years ago
7 0

Answer:

1034

Step-by-step explanation:

sleet_krkn [62]2 years ago
6 0

Answer:

1034

Step-by-step explanation:

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Last night, 80 people attended a lecture at the Smithville Public library. 47 of the attendees were men. What ratio BEST represe
Ganezh [65]
Number of people: 80

Number of Men: 47
Number of Women: 33

Ratio that best represents the number of men and the number of women:
47 : 33
6 0
3 years ago
Read 2 more answers
How do you take the antiderivative of (sinxcosx)^2?
gtnhenbr [62]
<span>∫(sinx cosx)^2dx = ∫(1/2sin 2x)^2 dx = 1/4∫sin^2 2x dx = 1/4∫1/2(1 - cos 4x)dx = 1/8∫(1 - cos 4x) dx = 1/8[x - sin 4x / 4] + c = 1/32(4x - sin 4x) + c
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8 0
3 years ago
Raju is cycling at a speed of 30km/h. He applies brakes and stops at a junction in 10s. Calculate the acceleration.
Sedbober [7]

Answer:

Acceleration = 3m/s²

Step-by-step explanation:

Here ,

Initial velocity = 30km/h

Final velocity = 0km/h

Time = 10s

Acceleration = ?

We know ,

A = v-u/t

or , A = 0-30/10

or, A = 30/10

A = 3m/s²

Therefore the acceleration is 3m/s²

7 0
2 years ago
Software to detect fraud in consumer phone cards tracks the number of metropolitan areas where calls originate each day. It is f
pashok25 [27]

Answer:

0.999987

Step-by-step explanation:

Given that

The user is a legitimate one = E₁

The user is a fraudulent one = E₂

The same user originates calls from two metropolitan areas  = A

Use Bay's Theorem to solve the problem

P(E₁) = 0.0131% = 0.000131

P(E₂) = 1 - P(E₁)  = 0.999869

P(A/E₁) = 3%  = 0.03

P(A/E₂) = 30% = 0.3

Given a randomly chosen user originates calls from two or more metropolitan, The probability that the user is fraudulent user is :

P(E_2/A)=\frac{P(E_2)\times P(A/E_2)}{P(E_1)\times P(A/E_1)+P(E_2)\times P(A/E_2)}

=\frac{(0.999869)(0.3)}{(0.000131)(0.03)+(0.999869)(0.3)}

\frac{0.2999607}{0.00000393+0.2999607}

\frac{0.2999607}{0.29996463}

= 0.999986898 ≈ 0.999987

6 0
3 years ago
Few drivers realize that steel is used to keep the road surface flat despite the weight of buses and trucks. Steel bars, deeply
Mrrafil [7]

Answer: Is reinforced with other material

Step-by-step explanation:

The options are:

A is expensive to build.

B usually cracks under heavy weights.

C looks like any other road.

D is reinforced with other material.

The passage best supports the statement that a concrete road are reinforced with other material. According to the information given in the passage, steel plays a vital role in keeping the road surface flat.

Steel bars are embedded in concrete so that the stresses cannot crack the slab. Therefore, it indicates that concrete road is reinforced with other material.

4 0
2 years ago
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