If y=-0.8 when x=2 find the y when x=3
1 answer:
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The system of inequalities that best describes this situation provided A represents the area in which the entire field exists:
Word problems in mathematics exist methods we can utilize variables, algebra notations, and arithmetic operations to solve real-life cases.
We have a new addition to the current rectangular field,
Let that new addition to the current rectangular field be x
Length of the new addition = 10x
Twice the width of the new addition = 2x²
Original area of the field = 300
From the above information, we can derive a quadratic equation:
2x² + 10x + 300
Also, we exist given a constraint that the total area of the practice field should be no more than 1200.
It can be less than 1200 or equivalent to 1200.
Therefore, the system of inequalities that best describes this situation provided A represents the area in which the entire field exists:
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Answer:
Now we can calculate the p value with the following probability
If we use the commonly significance level of 0.05 we see that the p value is lower than these values we can conclude that the true mean is different from the value of 465.6 at 5% of significance
Step-by-step explanation:
Data provided
represent the mean score on the standardized memory test
represent the population standard deviation
sample size
represent the value that we want to verify
z would represent the statistic
represent the p value
System of hypothesis
We are interested to check if the memory performance for elderly individuals differs from that of the general population (mean different from 465.6), the system of hypothesis are then:
Null hypothesis:
Alternative hypothesis:
Since we know the population deviation we can use the z statistic from the z test for the true mean:
(1)
Replacing the info given we got:
Now we can calculate the p value with the following probability
If we use the commonly significance level of 0.05 we see that the p value is lower than these values we can conclude that the true mean is different from the value of 465.6 at 5% of significance