the number of students in Collins school is more than double the numbers of students in Montgomery school which are 290 what is
the least number of students that could attend Collins school?
2 answers:
Collins # of student > double # of Montgomery students
C > 2M M=290 290 x 2 = 580
Since Collins is MORE than double, and double is 580, the least amount should be 581.
A: 581
(Please correct me if I’m wrong)
Answer:
Minimum number of Collins school students will be 581.
Step-by-step explanation:
Let the number of student in Collins school is C and number of students in Montgomery school is M.
Now the expression representing "the students in Collins school is more than double the numbers of students in Montgomery school" will be
C > 2M
If the students in Montgomery school are 290 then by the expression written above C > 2×290
C > 580
Therefore, minimum number of Collins school students will be 581.
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