All categories

3 years ago

Plz help I have a time limit

Mathematics

1 answer:

vivado [14]3 years ago

3 0

Answer:

Area 108cm2

Step-by-step explanation:

triangle =1/2 ×base× height

rectangle =length × width

then add the area of each shape

You might be interested in

Need help quick not many points cause I'm low on them will make it brainlies answer if right

adoni [48]

I think the answer is B.

7 0

3 years ago

Prove algebraically that r = 10/2+2sinTheta is a parabola

Xelga [282]

Answer:

$y = - \frac{ 1 }{10} {x}^{2} + \frac{5}{2}$

Step-by-step explanation:

We want to prove algebraically that:

$r = \frac{10}{2 + 2 \sin \theta}$

is a parabola.

We use the relations

${r}^{2} = {x}^{2} + {y}^{2}$

and

$y = r \sin \theta$

Before we substitute, let us rewrite the equation to get:

$r(2 + 2 \sin \theta) = 10$

$r(1+ \sin \theta) = 5$

Expand :

$r+ r\sin \theta= 5$

We now substitute to get:

$\sqrt{ {x}^{2} + {y}^{2} } + y = 5$

This means that:

$\sqrt{ {x}^{2} + {y}^{2} }=5 - y$

Square:

${x}^{2} + {y}^{2} =(5 - y)^{2}$

Expand:

${x}^{2} + {y}^{2} =25 - 10y + {y}^{2}$

${x}^{2} =25 - 10y$

${x}^{2} - 25 = - 10y$

$y = - \frac{ {x}^{2} }{10} + \frac{5}{2}$

This is a parabola (0,2.5) and turns upside down.

4 0

3 years ago

Suppose that P(A) = 0.25 and P(B) = 0.40 . If P(A|B)=0.20 , what is P(B|A) ?

Ket [755]

Answer:

0.32

Step-by-step explanation:

Use of formula:

P(A and B) = P(A)*P(B|A) and
P(A and B) = P(B)*P(A|B)

According to above and based on given:

P(A)P(B|A) = P(B)P(A|B)
P(B|A) = P(A|B)*P(B)/P(A)
P(B|A) = 0.20*0.40/0.25 = 0.32

8 0

3 years ago

The zeros of function d are -3 and 8. Which expression could be a factor of function d?

marysya [2.9K]

X+3 or x-8
These answers will both work!

8 0

3 years ago

I Need. Dis quickly my sis will get mad

blsea [12.9K]

Answer:

can I see a copy of the picture? I will edit answer once I can see the picture of the gingerbread man

3 0

3 years ago