<span>3y^2 • 4x^2y • 5x = (3*4*5) * (</span><span>y^2 * y) * (</span><span>x^2*x) = 60 * y^3 * x^3 = 60 (xy)^3
</span>where ((<span>y^2 * y)) adding the powers in case of multiplication
and also for this:</span><span> (<span>x^2*x)</span> </span>
Answer:
We have to use the formule to calculate the vertex which is: V(-b/2a;4ac-b^2/4a)
A) y=x+7 where a=1 b=0 and c=7
By replacing we have: V(0;28/4) V(0;7)
B) y=-x where a=-1 b and c=0 so V(0,0)
1/4 of 52 = 13.
you didn't list the options....
Answer with explanation:
Given : The computed r -value = 0.45
Sample size : n=18
Degree of freedom : 
Now, the critical value for Pearson correlation coefficient for a two-tailed test at a .05 level of significance will be :
( by critical correlation coefficient table)
Since , 
i.e. 0.45>0.468 , then we say that his Pearson correlation coefficient is not significant for a two-tailed test at a .05 level of significance.
Answer:
4.04 metros
Step-by-step explanation:
Resolvemos la pregunta anterior usando la función trigonométrica de
tan θ = Opuesto / Adyacente
θ = 60 °
Frente = 7 metros
Adyacente =? = x
Por eso
bronceado 60 = 7 / x
Multiplicar cruzada
= tan 60 × x = 7
x = 7 / tan 60
x = 4.0414518843 metros
Aproximadamente = 4.04 metros
