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geniusboy [140]
2 years ago
12

Yohan Blake ran the 100-meter race in the 2012 Olympics in 9.75 seconds. Compare the speeds if he ran the 200-meter race in 19.5

seconds.

Mathematics
2 answers:
lakkis [162]2 years ago
8 0

Sorry for the late response :<

Answer:

The unit rates would be comparable for both races. So, his speed is going to be the same for both races.

<3

Step2247 [10]2 years ago
6 0

Answer:

This person gave the correct answer

Step-by-step explanation:

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drek231 [11]
The range is (10,11.5,12.5,13.75)
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3 years ago
PLEASE HELP GONNA FAIL WILL GIVE BRAINLESS
vazorg [7]

Answer: P = 166 units

Step-by-step explanation: Each point on the triangle has lines that are tangent to the circle in the triangle, meaning that those lines form a 90° angle to the middle point in the circle. There is also a rule that states if there are tangent lines coming from the points and if the points have at least one given side length, the other side will have the same side length. So if one side on point D is 41, then the other side connected to the point is 41. I added up all of the side lengths; 41 + 41 + 30 + 30 + 12 +12 = 166 units.

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What is the value of x?<br><br><br><br> Enter your answer in the box.<br><br> x =
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7 0
3 years ago
over a two week period Julie had the following number of math homework problems given each day:20,0,7,10,11 0,25,15,1 find the m
kvv77 [185]
Mean: Add all the numbers and divide by the amount of numbers.

20 + 0 + 7 + 10 + 11 + 0 + 25 + 15 + 1 = 89
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Mean = 9.889 (rounded)

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3 0
3 years ago
Read 2 more answers
Thethree sides of a triangle measure 810 and 12 units is this a right angle?
Alja [10]

Answer:

The given triangle is NOT A RIGHT ANGLED TRIANGLE.

Step-by-step explanation:

Here, the three given sides of the triangle are:

8 units, 10 units and 12 units

Now, for any triangle to be a right angle:

by the PYTHAGORAS THEOREM:

(Base)^2 + (Perpendicular)^2  = (Hypotenuse)^2

The longest of all sides id the hypotenuse.

⇒ H  = 12 units

Let us assume, B = 8 units, P = 10 units

Now, here checking the condition:

(8)^2  + (10)^2  = 64  + 100  = 164  \neq (12)^2  = 144\\\implies (B)^2  + (P)^2  \neq (H)^2

Hence, the given triangle is NOT A RIGHT ANGLED TRIANGLE.

4 0
3 years ago
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