Answer:
Tn = 2/3^(n-1)
Step-by-step explanation:
The nth term of a geometric progression is expressed as
Tn = ar^{n-1}
a is the first term
n is the number of terms
r is t common ratio
From the sequence
a = 2/9
r = (2/3)/(2/9) = 2/(2/3) =3
Substitute
Tn = 2/9(3)^(n-1)
Hence the required equation is Tn = 2/3^(n-1)
B = 50 & C = 130
I really don't know how to explain but 180 - 50 = 130 for C and 50 is the measurement for B
Slope(gradient)=
Good luck!
Intelligent Muslim,
From Uzbekistan.
