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4 years ago

Identify a pair of vertical angles in the figure.A. and B. and C. and D. and

Mathematics

1 answer:

diamong [38]4 years ago

4 0

Can i see the picture please nut if it was like mine i would say a

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Use a graphing calculator to find the solutions to each system. <br> 17) y=2^x<br> y=x+5

MaRussiya [10]

İf you find problem respond me

Where are youbfrom answer please

6 0

3 years ago

A cylinder with a 2 centimeter diameter is drilled through the triangular prism shown on the left find the volume of the prism

saw5 [17]

Answer:

The volume of a prism on its own = 248.5cm^3

The volume of a cylinder = 87.92cm^3

Step-by-step explanation:

The volume does not change for the prism as the hole was drilled.

We can show the drilled space with v(l) and (p) for prism V

v(l) 248.5p - 87.92p + 87.92p

= 248.5p

3 0

3 years ago

What is the range for the possible side length AB of ABC?

julia-pushkina [17]

Answer:

2 < AB < 18

Step-by-step explanation:

5 0

2 years ago

Flow meters are installed in urban sewer systems to measure the flows through the pipes. In dry weatherconditions (no rain) the

ziro4ka [17]

Answer:

a) $\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

b) For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

Step-by-step explanation:

423.6, 487.3, 453.2, 402.9, 483.0, 477.7, 442.3, 418.4, 459.0

Part a

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case we need to find the sample standard deviation with the following formula:

$s=sqrt{\frac{\sum_{i=1}^8 (x_i -\bar x)^2}{n-1}}
And in order to find the sample mean we just need to use this formula:
[tex]\bar x =\frac{\sum_{i=1}^n x_i}{n}$

The sample deviation for this case is s=30.23

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=9-1=8$

The Confidence interval is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and the critical values are:

$\chi^2_{\alpha/2}=20.09$

$\chi^2_{1- \alpha/2}=1.65$

And replacing into the formula for the interval we got:

$\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

Part b

For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

4 0

3 years ago

Paul has 6 teaspoons of salt. The ratio of teaspoons to tablespoons is 3:1. How many tablespoons of salt does Paul have?

dalvyx [7]

Answer:

2 tablespoons of salt

Step-by-step explanation:

If 3 teaspoons are equal to 1 tablepoon, we can divide the 6 tablespoons by 3 to get our answer of 2 tablespoons.

(sorry if this is confusing but I hope it helped)

7 0

3 years ago