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Evgen [1.6K]
3 years ago
8

I need help understanding problem number 2

Mathematics
1 answer:
HACTEHA [7]3 years ago
6 0

Step-by-step explanation:

(<em>2</em><em>×</em><em>2</em><em>)</em><em> </em><em>.</em><em> </em>2<em>×</em><em>2</em><em>×</em><em>2</em><em>×</em><em>2</em><em> </em><em>. </em><em> </em>2×2×2

=(4) . 16 . 8

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What is the sum of 2 + 0.42 + 1.8?
Inessa [10]
The answer is a, you add the numbers up get 4.22 which is equivalent to 4 whole aka ones and since .22 is a decimal you use your tenths and hundredths
4 0
3 years ago
Anybody help me to solve this question. ​
Mumz [18]

Answer:

\dfrac{1}{(b-c)},\dfrac{1}{(c-a)} ,\dfrac{1}{(a-b)} are\ in\ AP

Step-by-step explanation:

Given that (b-c)^2, (c-a)^2 , (a-b)^2 are in AP

To prove: \dfrac{1}{(b-c)},\dfrac{1}{(c-a)} ,\dfrac{1}{(a-b)} are in AP

From given as we know if p , q, r are in AP then 2q= p+r.

2(c-a)^2= (b-c)^2+(a-b)^2\\\\\Rightarrow 2(c^2+a^2-2ac)=b^2+c^2-2bc+a^2+b^2-2ab\\\\\Rightarrow 2c^2+2a^2-4ac= 2b^2+c^2+a^2 -2bc-2ab\\\\\Rightarrow a^2+c^2-2b^2-4ac= -2bc-2ab\\\\\Rightarrow a^2-2b^2+c^2= 4ac-2bc-2ab

Now

\dfrac{1}{(b-c)},\dfrac{1}{(c-a)} ,\dfrac{1}{(a-b)}2\dfrac{1}{(c-a)} =\dfrac{1}{(b-c)}+\dfrac{1}{(a-b)}\\\\\Rightarrow \dfrac{2}{(c-a)}= \dfrac{a-b+b-c}{(b-c)(a-b)} \\\\\Rightarrow \dfrac{2}{(c-a)}= \dfrac{a-c}{(b-c)(a-b)} \\\\\Rightarrow2(b-c)(a-b) = (c-a)(a-c) \\\\\Rightarrow 2(ab-b^2-ac+bc)= -(a-c)^2\\\\\Rightarrow 2ab- 2b^2-2ac+2bc = -a^2-c^2+2ac\\\\\Rightarrow a^2-2b^2+c^2=4ac-2ab-2bc

Which is the result of AP

.

Hence proved

6 0
3 years ago
1
ArbitrLikvidat [17]

Answer:

18 girls

Step-by-step explanation:

6:9

6+9 = 15

we multiply each part of the ratio by 3

6*3 = 18 girls

9*3 = 27 boys

6 0
3 years ago
Please help me please help me
Pachacha [2.7K]

Answer:

C=66, C=25 1/7

Step-by-step explanation:

i

C=pi(d)

C=22/7*21

C=66

ii

C=pi(d)

C=22/7*16

C=25 1/7

3 0
3 years ago
The perimeter of the parallelogram is 62 cm.
Marina86 [1]
Flldkxlcclckk 929292 o
8 0
2 years ago
Read 2 more answers
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