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lukranit [14]
3 years ago
9

Which best defines the relashionship between speed and velocity 1.speed is velocity with displacement 2.velocity is speed with d

isplacement 3. Speed is based on a specific direction 4. Velocity is based on distance
Mathematics
1 answer:
katrin [286]3 years ago
3 0

Answer:

  3.  Speed is based on a specific direction

Step-by-step explanation:

Generally, speed is a scalar quantity equal to the magnitude of velocity. Velocity is a vector quantity that is speed together with a specific direction.

The answer choice that seems most in agreement with this description seems to be ...

  3. Speed is based on a specific direction

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Find the value of the variable.
Zielflug [23.3K]

Answer:

x = 8, y = 8\sqrt{2}

Step-by-step explanation:

a^2+b^2=c^2

8^2+8^2=c^2      Both 8 and x sides are congruent so they're equal.

64+64=c^2      Add 64 + 64.

c^2=128           Square root 128

c^2=8\sqrt{2}

Final answers: x = 8, y = 8\sqrt{2}

3 0
3 years ago
Read 2 more answers
A ticket for a school musical is $12. There is a 5% transaction fee if the ticket is purchased online. What is the total cost of
gulaghasi [49]

Answer: The cost of a ticket bought online is $12.60.

Step-by-step explanation: First, we need to find the value of the transaction fee. Multiply 12 and 5%.

$12 x 0.05 = $0.60.

Now we have the fee. Lets add the fee with the original cost.

$12 + $0.60 = $12.60.

Therefore, we can conclude that the cost of a ticket that is purchased online is $12.60.

3 0
3 years ago
Find the 78th term of the arithmetic sequence<br> -12,-13,-14,
creativ13 [48]

Answer:

  -89

Step-by-step explanation:

The first term of the sequence is a1 = -12.

The common difference between terms is ...

  d = -13 -(-12) = -1

The generic term is given by ...

  an = a1 +d(n -1)

Then the 78th term is ...

  a78 = -12 +(-1)(78 -1) = -12 -77

  a78 = -89

8 0
2 years ago
Would appreciate the help ! ​
aleksandr82 [10.1K]

This is one pathway to prove the identity.

Part 1

\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{1}{\tan(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\cot(\theta) = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{\cos(\theta)}{\sin(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)*\sin(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)(1-\cos(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\

Part 2

\frac{\sin^2(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)-\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-(\cos(\theta)-\cos^2(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-\cos(\theta)+\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\

Part 3

\frac{\sin^2(\theta)+\cos^2(\theta)-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1}{\sin(\theta)} = \frac{1}{\sin(\theta)} \ \ {\checkmark}\\\\

As the steps above show, the goal is to get both sides be the same identical expression. You should only work with one side to transform it into the other. In this case, the left side transforms while the right side stays fixed the entire time. The general rule is that you should convert the more complicated expression into a simpler form.

We use other previously established or proven trig identities to work through the steps. For example, I used the pythagorean identity \sin^2(\theta)+\cos^2(\theta) = 1 in the second to last step. I broke the steps into three parts to hopefully make it more manageable.

3 0
2 years ago
Multiply and simplify<br>(x + 3)(x - 8)<br>a) 2x-24<br>b) x2-5x+24<br>c) x2- 5x-24<br>dx2- 8x - 24​
andrezito [222]
The answer is C X^2-5x-24
4 0
2 years ago
Read 2 more answers
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