Answer:
38.5
Step-by-step explanation:
7/2 = 3.5. 11×3.5= 38.5
Answer:
P(A∩B) = 0.522
Step-by-step explanation:
Let's call A the event that a puppy is adopted and B the probability that a puppy live 7 or more years
So, the probability P(A∩B) that a randomly selected puppy in the shelter will get adopted and live 7 or more years is:
P(A∩B) = P(A)*P(B/A)
Because A and B are not independents.
Then, the probability P(A) that a puppy is adopted is 58% and the probability P(B/A) that a puppy live 7 or more years given that the puppy is adopted is 90%.
Finally, replacing the values, we get:
P(A∩B) = 0.58*0.9 = 0.522
It means that the 52.2% of the puppies are adopted and live 7 or more years.
Answer:
T=50.99
Step-by-step explanation:
Given:
I=3,875.78
P=1,900
R=4% I.e 4/100 , 0.04
T=?
I=PRT
3,875.79=($1,900)(0.04)t
3,875.79=76t
3,875.79/76= t
T=50.99
