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Sati [7]
3 years ago
13

Is 432 a perfect cube?​

Mathematics
1 answer:
Vika [28.1K]3 years ago
4 0

Answer:

no its not a perfect cube.

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What is the product of 3.8 and .69?​
Verdich [7]

Answer:

2.622

Step-by-step explanation:

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Please help me with this<br> I'll mark you as brainliest
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a) Just add 1 square on the right and 1 square on top for figure 4. Add 1 more in each place for figure 5.

b) Each stage adds a square above and a square to the right. The pattern never decreases. This trend is shown by figures 1, 2, and 3.

c) Figure 0 would be a single square. Simply follow the pattern in reverse. As the figure number decreases, squares are removed from the right and the top rather than added.

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Explain the differences between properties of equality and properties of inequality when solving equations and inequalities.
matrenka [14]
Equalities will have the words "is" or "equals" or "the same as" in the wording. These produce a unique solution.

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lana66690 [7]
0.7154 is the product for 0.98×0.73
5 0
3 years ago
find the work done by a person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long (i
tankabanditka [31]

The work done in pushing the box is 64000 lb-ft²/s²

<h3>How to calculate the work done by the person?</h3>

Since person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long, the work done, W is

W = mgh where

  • m = mass of box = 40 lb,
  • g = acceleration due to gravity = 32 ft/s² and
  • h = height of incline = LsinФ where
  • L = length of incline = 100 ft and
  • Ф = angle of incline = 30°

So, W = mgh

W = mgLsinФ

So, substituting the values of the variables into the equation, we have

W = mgLsinФ

W = 40 lb × 32 ft/s² × 100 ftsin30°

W = 1280 lb-ft/s² × 100 ft × 0.5

W = 1280 lb-ft/s² × 50 ft

W = 64000 lb-ft²/s²

So, the work done in pushing the box is 64000 lb-ft²/s²

Learn more about work done here:

brainly.com/question/25970931

#SPJ1

3 0
1 year ago
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