Solve the following system by Elimination:
{7 x + 3 y = 22 | (equation 1)
{4 y = 20 | (equation 2)
Divide equation 2 by 4:
{7 x + 3 y = 22 | (equation 1)
{0 x+y = 5 | (equation 2)
Subtract 3 × (equation 2) from equation 1:
{7 x+0 y = 7 | (equation 1)
{0 x+y = 5 | (equation 2)
Divide equation 1 by 7:
{x+0 y = 1 | (equation 1)
{0 x+y = 5 | (equation 2)
Collect results:
Answer: {x = 1, y = 5
_____________________________________________________
Solve the following system:
{y - 2 x = 10 | (equation 1)
{4 x - y = -14 | (equation 2)
Swap equation 1 with equation 2:
{4 x - y = -14 | (equation 1)
{-(2 x) + y = 10 | (equation 2)
Add 1/2 × (equation 1) to equation 2:
{4 x - y = -14 | (equation 1)
{0 x+y/2 = 3 | (equation 2)
Multiply equation 2 by 2:
{4 x - y = -14 | (equation 1)
{0 x+y = 6 | (equation 2)
Add equation 2 to equation 1:
{4 x+0 y = -8 | (equation 1)
{0 x+y = 6 | (equation 2)
Divide equation 1 by 4:
{x+0 y = -2 | (equation 1)
{0 x+y = 6 | (equation 2)
Collect results:
Answer: {x = -2, y = 6
Answer:
Step-by-step explanation:
3a-2b=14 multiply by 3
9a - 6b = 42 (1)
4a+3b=13 multiply by 2
8a +6b = 26 (2)
sum up (1) and (2)
17a = 68
a =4
b=-1
The brackets make the answer positive so you were just do 48÷6 which is 8and then 35÷7 which is five and you add 8+5 and you get 13
