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2 years ago

Find the greatest common factor and the least common multiple of 16 and 20. The prime factorizations of each number are given.

Mathematics

1 answer:

11111nata11111 [884]2 years ago

4 0

Answer:

i feel like its that one number

Step-by-step explanation:

i found one

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A square wrestling mat has a side length of (4x - 1) feet.

son4ous [18]

Answer:

$(4x-1)^2$

Step-by-step explanation:

Area of a square = $l^2$

If l = $(4x - 1)$ ,

Then area = $(4x - 1)^2$

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2 years ago

What is the Length of x?

Lady bird [3.3K]

Answer:

3.17

Step-by-step explanation:

2.5/1.5 = 1.66667, 1.66667 (it goes on infinitely 1.6666 etc.)

1.66667 x 1.9 = 3.166666654, and when rounded to nearest tenth it is 3.17

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2 years ago

Solve for x.<br> 5x – 31 = 23 - X<br> x = [?]

sergejj [24]

Answer:

X=9

Step-by-step explanation:

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1 year ago

Read 2 more answers

Please help I need the answer

ivolga24 [154]

Answer:

show this

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2 years ago

The restrictions on the variable in the division x+5/x+2 divided by x-3/x+1 are

oksian1 [2.3K]

Answer:

$x \neq-2 \text { and } x \neq-1$

Step-by-step explanation:

The restricted value is a value that makes the denominator of a function equal to zero. Thus, solving these function results in an undefined solution.

Thus, $x \neq-2$ and $x \neq-1$ are the restricted values for $\frac{x+5}{x+2}$ divided by $\frac{x-3}{x+1}$

Because, substituting $x=-2$ in $\frac{x+5}{x+2}$

Now, substituting $x=-2$ , we get,

$\begin{aligned}\frac{x+5}{x+2} &=\frac{x+5}{-2+2} \\&=\frac{x+5}{0}\end{aligned}$

Thus, results the solution undefined.

Also, substituting $x=-1$ in $\frac{x-3}{x+1}$

$\begin{aligned}\frac{x-3}{x+1} &=\frac{x-3}{-1+1} \\&=\frac{x-3}{0}\end{aligned}$

Thus results the solution undefined.

Hence, the restricted values are $x \neq-2 \text { and } x \neq-1$

7 0

2 years ago