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3 years ago

What 17 multiply and adds to get -2

Mathematics

2 answers:

Marrrta [24]3 years ago

8 0

17 * 0 + -2.

Now we rewrite the equation and make it 17 * 0 - 2 and u get -2.

Kisachek [45]3 years ago

6 0

If it was -19+17 the answer is -2

and for multiplication it's impossible to get -2 with 17 unless you try subtracting and adding then yes there's a change

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What is the mean of 320,294,265, and 301

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adding 320,294,265 and 301=1180

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J.k. Rowling and R.L. Stone are both ready hunger games . J.k. Reads 35 pages every 2 hours and R.L. Reads 45 pages every 3 hour

san4es73 [151]

Answer:

The rate of change for each reader is :

For J K Rowling : 17 and a half pages per hour

For R L Stone : 15 pages per hour

Step-by-step explanation:

Here the reading rate of each reader is given as:

J.K. Reads 35 pages every 2 hours.

So, the number of pages read by J K in 2 hours = 35 pages

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So, the pages read by J K Rowling in 1 hour is 17 and a half pages.

R L Stone reads 45 pages every 3 hours.

So, the number of pages read by R L in 3 hours = 45 pages

⇒ The number of pages read per hour = 45 / 3 = 15 pages

So, the pages read by R L Stone in 1 hour is 15 pages.

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For J K Rowling : 17 and a half pages per hour

For R L Stone : 15 pages per hour

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3 years ago

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Use the discriminant to determine the number of solutions to the quadratic equation 3x^2+5x=-1

kari74 [83]

Answer:

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Step-by-step explanation:

Hi there!

Background of the Discriminant

The discriminant $b^2-4ac$ applies to quadratic equations when they are organised in standard form: $ax^2+bx+c=0$ .

All quadratic equations can be solved with the quadratic formula: $x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}}$ .

When $b^2-4ac$ is positive, it is possible to take its square root and end up with two real, distinct values of x.

When it is zero, we won't be taking the square root at all and we will end up with two real solutions that are equal, or just one solution.

When it is negative, it is impossible to take the square root and we will end up with two non-real solutions.

Solving the Problem

$3x^2+5x=-1$

We're given the above equation. It hasn't been organised completely in $ax^2+bx+c=0$ , but we can change that by adding 1 to both sides to make the right side equal to 0:

$3x^2+5x+1=0$

Now that we can identify the values of a, b and c, we can plug them into the discriminant:

$D=b^2-4ac\\D=(5)^2-4(3)(1)\\D=25-4(3)(1)\\D=25-12\\D=13$

Therefore, because the discriminant is positive, the equation has two real, distinct solutions.

I hope this helps!

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