Order from greatest to least.03 .0 .32. 07 .7
1 answer:
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Answer:
74.86% probability that a component is at least 12 centimeters long.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Variance is 9.
The standard deviation is the square root of the variance.
So
Calculate the probability that a component is at least 12 centimeters long.
This is 1 subtracted by the pvalue of Z when X = 12. So
has a pvalue of 0.2514.
1-0.2514 = 0.7486
74.86% probability that a component is at least 12 centimeters long.
Remember that the area of a square is just one of its sides squared. 
where
is the area of the square
is one of the sides of the square
Unit square is a square whose sides have length 1, so lets use our formula to find the volume of one unit square:
We now know that each one of the squares has area 1 unit squared. Since there are 28 unit square in our figure, we are going to multiply the area of a unit square by 28 to find the area of our figure:
Area of the figure=
units squared
We can conclude that the area of the figure is 28 units squared.
where
Unit square is a square whose sides have length 1, so lets use our formula to find the volume of one unit square:
We now know that each one of the squares has area 1 unit squared. Since there are 28 unit square in our figure, we are going to multiply the area of a unit square by 28 to find the area of our figure:
Area of the figure=
We can conclude that the area of the figure is 28 units squared.