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3 years ago

Please need this by the 16th

Mathematics

2 answers:

lukranit [14]3 years ago

8 0

Answer:

7/12= 35/60

7/15= 28/60

Pani-rosa [81]3 years ago

7 0

Answer:

Step-by-step explanation:

12 can be broken into 3*4

15 = 5*3

The least factors are

3*4*5 = 60

The lowest common denominator is 60

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A simple random sample of 20 days in which Parsnip ate seeds was selected, and the mean amount of time it took him to eat the se

bearhunter [10]

Answer:

$(14.5-13.9) -1.69 \sqrt{\frac{3.98^2}{20}+ \frac{4.03^2}{17}} = -1.63$

$(14.5-13.9) +1.69 \sqrt{\frac{3.98^2}{20}+ \frac{4.03^2}{17}} = 2.83$

And the confidence interval for this case $-1.63 \leq \mu_1 -\mu_2 \leq 2.83$

Step-by-step explanation:

We know the following info from the problem

$\bar X_1 = 14.5$ sample mean for the group 1

$s_1 = 3.98$ the standard deviation for the group 1

$n_1= 20$ the sample size for group 1

$\bar X_2 = 13.9$ sample mean for the group 2

$s_1 = 4.03$ the standard deviation for the group 2

$n_2= 17$ the sample size for group 2

We have all the conditions satisifed since we have random samples.

We want to construct a confidence interval for the true difference of means and the correct formula for this case is:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}$

The degrees of freedom are given :

$df = n_1 +n_2- 2 = 20+17-2=35$

The confidence level is 0.9 or 90% and the significance level is $\alpha=1-0.9=0.1$ and $\alpha/2 = 0.05$ and the critical value for this case is:

$t_{\alpha/2} = 1.69$

And replacing the info given we got:

$(14.5-13.9) -1.69 \sqrt{\frac{3.98^2}{20}+ \frac{4.03^2}{17}} = -1.63$

$(14.5-13.9) +1.69 \sqrt{\frac{3.98^2}{20}+ \frac{4.03^2}{17}} = 2.83$

And the confidence interval for this case $-1.63 \leq \mu_1 -\mu_2 \leq 2.83$

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3 years ago

Give the reason for the steps used in solving the equation 3(x - 4) + 5 = 2x - 2(3 - x)

STALIN [3.7K]

$3(x - 4) + 5 = 2x - 2(3 - x) \\ 3x - 12 + 5 = 2x - 6 + 2x \\ 3x - 7 = 4x - 6 \\ 3x - 4x - 7 + 6 = 0 \\ - x - 1 = 0 \\ x = - 1$

Please give brainliest

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2 years ago

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Craig is practicing his baseball pitching he kept track of the speed oI made a histogram at right can you tell the speed of each

LenKa [72]

Step-by-step explanation:

I am not sure, if something else is missing.

but given that one chart we can say that Craig had 2 fastest throws.

they were in the category 70-75 mph.

but we cannot say precisely which one was faster, and how fast it went.

it is also not clear what is the categorization of a border element (e.g. with an exact speed of 60 mph - is it in the 55-60 or in the 60-65 category ? or both ?).

I assume the upper limit of each interval is included, and the lower limit is excluded.

under this assumption we can say the fastest pitch was faster than 70 mph but slower than or equal to 75 mph.

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2 years ago

What is the measure of angle A?

Ilya [14]

Answer:

Step-by-step explanation:

O is double D. And A is equal to O. Hence 2*48=96

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3 years ago

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The amount of sales tax on a new car is directly proportional to the purchase price of the car. Victor bought a new car for $30,

Airida [17]

Answer:

Rita paid 47,500 dollars for the purchase price.

Step-by-step explanation:

We are given the sales tax on a new car is directly proportional to the purchase price of the car which means there is is something k such that

when you multiply it to the sales tax you get the purchase price.

Let's set this equation:

y=kx

Let y represent the purchase price and x the sales tax.

The second sentence tells us that (x,y)=(1500,30000).

We can plug this into y=kx to find the constant k. (Constant means it stays the same no matter what the input and output is).

So we have:

30000=k(1500)

300 =k(15) I went ahead and divided previous equation by 100.

Now divide both sides by 15:

300/15=k

Simplify:

20=k

So the equation to use the answer the question is

y=20x

where y is purchase price and x is sales tax.

So we want to know the purchase price on a car if the sales tax is 2375.

So replace x with 2375:

y=20(2375)

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3 years ago

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