Question

If you create a matrix, C, to show the inventory at the end of July, the value of the entry represented by C22 is ?

Answer 1

Answer:

$C_{22} = 389$

$Max(A_{31}) =376$

Step-by-step explanation:

Given

See attachment for complete question

Solving (a): The entry C22

First, matrix C represents the inventory at the end of July.

The entry of C is calculated as:

$C = Inventory - Sales$

i.e.

$C = \left[\begin{array}{ccc}543&356&643\\364&476&419\\376&903&409\end{array}\right] - \left[\begin{array}{ccc}102&78&97\\98&87&59\\54&89&79\end{array}\right]$

$C = \left[\begin{array}{ccc}543-102&356-78&643-97\\364-98&476-87&419-59\\376-54&903-89&409-79\end{array}\right]$

$C = \left[\begin{array}{ccc}441&278&546\\266&389&360\\322&814&330\end{array}\right]$

Item C22 means the entry at the second row and the second column.

From the matrix

$C_{22} = 389$

Solving (b): The maximum A31 possible.

From the given data, we have:

$Inventory = \left[\begin{array}{ccc}543&356&643\\364&476&419\\376&903&409\end{array}\right]$

$Unit\ Sales = \left[\begin{array}{ccc}102&78&97\\98&87&59\\54&89&79\end{array}\right]$

From the matrices above.

A31 means entry at the 3rd row and 1st column.

So, the possible values of A31 are:

$A_{31} = 376$

and

$A_{31} = 54$

By comparison, 376 > 54

So:

$Max(A_{31}) =376$