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matrenka [14]
3 years ago
12

Which is the graph 3x + 5y=-15

Mathematics
1 answer:
matrenka [14]3 years ago
8 0

It's a linear function. We need only two points to the plotting of the graph.

3x+5y=-15\qquad\text{subtract 3x from both sides}\\\\5y=-3x-15\qquad\text{divide both sides by 5}\\\\y=-\dfrac{3}{5}x-3\\\\for\ x=0\to y=-\dfrac{3}{5}(0)-3=0-3=-3\to(0,\ -3)\\\\for\ x=-5\to y=-\dfrac{3}{5}(-5)-3=-3+3=0\to(-5,\ 0)

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C . Is the answer
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4 years ago
Harold is twice as old as Jack, who is three years older than Dan. If Harold's age is five times Dan's age, how old in years is
never [62]
Dan's age is x.
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2(x+3)=5x \\
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4 0
3 years ago
Read 2 more answers
Find (4/5+3/6-5/12) ÷ 2/3​
slavikrds [6]

Answer:

1/2 + 2/3 + 5/4 = 29/ 12 = 2 5/  12  ≅ 2.4166667

Step-by-step explanation:

Add: 1/ 2  + 2/ 3  = 1 · 3/ 2 · 3  + 2 · 2/ 3 · 2  = 3/ 6  + 4/ 6  = 3 + 4/ 6  = 7/ 6

For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of both denominators - LCM(2, 3) = 6. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 2 × 3 = 6. In the next intermediate step, the fraction result cannot be further simplified by canceling.

In words - one half plus two thirds = seven sixths.

Add: the result of step No. 1 + 5/ 4  = 7/ 6  + 5/ 4  = 7 · 2/ 6 · 2  + 5 · 3/ 4 · 3  = 14/ 12  + 15/ 12  = 14 + 15/ 12 = 29/ 12

For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of both denominators - LCM(6, 4) = 12. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 6 × 4 = 24. In the next intermediate step, the fraction result cannot be further simplified by canceling.

In words - seven sixths plus five quarters = twenty-nine twelfths.

<em>hope it helps...</em>

<em>correct me if I'm wrong...</em>

7 0
3 years ago
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