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3 years ago

If $5,000,000 were invested at 4% interest compound continuously, how much will the investment be worth in 30 years?

Mathematics

1 answer:

Lerok [7]3 years ago

6 0

If $5,000,000 is invested at 4% interest compounded continuously, the investment will be worth $16,215,000 in 30 years.

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What value of n makes the equation ? 4(0.5-3)=n-0.25(12-8n)

Free_Kalibri [48]

Answer:

4(0.5-3)=n-0.25(12-8n)

2-12=n-3+2n

-10=-3+3n

-10+3=3n

-7=3n

n=-2.3

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3 years ago

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The amount of money Deon earns working at a store is given in the table.

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Answer:

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Explanation:
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3 years ago

Which would best display the following data if you wanted to display the numbers which are outliers as well as the mean? [4, 1,

Serhud [2]

Arranging data in ascending order to identify the outlier and calculate the mean

Step-by-step explanation:

Given the data as: [4, 1, 3, 10, 18, 12, 9, 4, 15, 16, 32]

Arrange in ascending order

[1, 3, 4, 4, 9, 10, 12, 15, 16, 18, 32 ]

The outlier is 32

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Mean=sum of data set/number of data set

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3 years ago

Plz help math question

Lina20 [59]

Answer:

y = -2x +20

6x - 5y = 12

Put the value of y in 2nd equation

6x - 5( -2x +20 ) = 12

6x +10x -40 = 12

16x = 12 +40

16x = 52

x = 13/4

Putting the value of x in equation 1

y = -2x +20

y = -2(13/4 ) +20

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3 years ago

How long would it take you to double your money is the bank pays 3.6% interest, compounded

Lapatulllka [165]

Answer:

$t=19.25\ years$

Step-by-step explanation:

we know that

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$t=?\ years\\P=x\\r=3.6\%=3.6/100=0.036\\A=2x$

substitute in the formula above

$2x=x(e)^{0.036t}$

solve for t

simplify

$2=(e)^{0.036t}$

Apply ln both sides

$ln(2)=ln[(e)^{0.036t}]$

Applying property of exponents

$ln(2)=[0.036t]ln(e)$

Remember that ln(e) =1

$ln(2)=[0.036t]$

$t=ln(2)/[0.036]$

$t=19.25\ years$

7 0

3 years ago