CD is called the middle base and is equal to :(AB + EF)/2
CD = <span>(AB + EF)/2
4x = [(x</span>²+10) + (8-x)]/2
8x = x²+10+8-x
8x= x²-x+18
x²-9x+18 = 0
x' = [-b+√(b²-4.a.c)]/2a & x" = [-b-√(b<span>²-4.a.c)]/2a
x'= 6 and x" = 3, So we have2 values of x</span>
We call the ratio between two directly proportional quantities the constant of proportionality. When these two quantities may increase or decrease, the constant proportionality always remains the same
First simplify the one inequality, 6r + 30 greater than or equal to 12 just divide by 6 then subtract 30 from both sides of the inequality. You should get r is greater than or equal to -3. For this one you need to reverse the inequality symbol then divide both sides by -1 to get a positive r, and you get r is less than -12. It's not A because there's two solutions, and it's not D for the same reason. It's not C because r isn't greater than -12. In conclusion it's B because it correctly represents the solutions that make the inequality true. I hope this helps you on your high school application :)
Answer:
- <u><em>g∘f (0) = 1</em></u>
Explanation:
The <em>composition</em> of the <em>functions</em> f and g represented by g ∘ f ( 0 ) means that g is applied to f(0), i.e f(0) is the input to the function g.
Since f(0) = 1, you are going fo find g(1):

Answer:
a =12*sqrt(2)
Step-by-step explanation:
3. The Pythagorean theorem states
a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse
a^2 +21^2 = 27^2
a^2 +441 =729
Subtract 441 from each side
a^2 +441-441 = 729 -441
a^2 =288
Take the square root of each side
sqrt(a^2) = sqrt(288)
sqrt(xy) = sqrt(x)sqrt(y)
a = sqrt(144)sqrt(2)
a =12*sqrt(2)