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natta225 [31]
3 years ago
13

What are the constants in the equation 3x+2y+4

Mathematics
1 answer:
Natalija [7]3 years ago
8 0

Answer:

4

Step-by-step explanation:

The constant is the number without a variable, usually being added or subtracted from the variable but not multiplied or divided by it.

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Find the product (b-2at^2)(3b-3at^2)
Maurinko [17]

Answer: 3b^2-9bat^2+6a^2t^4

Step-by-step explanation:

To solve this problem you must apply the proccedure shown below:

- Apply the Distributive property.

- Remember that, according the exponents properties, when you multiply two powers with equal base, you must add the exponents.

- Add the like terms.

Therefore, you obtain that the product is the following:

(b-2at^2)(3b-3at^2)=3b^2-3bat^2-6bat^2+6a^2t^4=3b^2-9bat^2+6a^2t^4

8 0
3 years ago
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Find the perimeter and the area of the figure. Round answers to the nearest tenth.
vlada-n [284]

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3 years ago
3.0625 divided by 7 in long division
elena-14-01-66 [18.8K]

Answer:

the answer to your question is 0.4375

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3 years ago
The proliferation of the Internet has given rise to a new method of advertising, called spamming, that essentially is a more cos
Katen [24]
The number of potential customers reached by the company is the total number of people that received their promotional material

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A) give stating reasons five other angles each equal to x<br>b) prove that AECF is a parallelogram ​
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Simple Proof:

a) In the image, we know that ABCD is a parallelogram and that means opposite angel measures should be the same. We know that angel DCB is made up by angel 1 and 2, and angel DAB and DCB are equal and angel DAB is made up by angel 1 and <em>x</em>. So now we can conclude that angel <em>x</em> is equal to angel 2.

b) According to the definitions of a parallelogram, opposite angel measures have to be the same, while AECF have angle 1 to angel 1 and angel 2 to angel 1. We can conclude that AECF is <u>NOT</u> a parallelogram. (Sorry, you didn't give me the full question so some information remains unclear. )

7 0
3 years ago
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