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lana [24]
3 years ago
8

A number cube is rolled. What is the probability that it will land on a 2 or a 5?

Mathematics
2 answers:
Bezzdna [24]3 years ago
7 0

A cube has 6 sides. 2 and 5 are numbers on 2 of the cube's sides. The probability is therefore 2/6 which simplifies to 1/3 or ~33.3%

zimovet [89]3 years ago
3 0
It’s morn of its 292 thanks.
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How do u calculate the percentage if it is more than 100%? <br> Like for example 140%
artcher [175]

Work out the difference (increase) between the two numbers you are comparing.

Increase = New Number - Original Number.

Then: divide the increase by the original number and multiply the answer by 100.

% increase = Increase ÷ Original Number × 100.

5 0
3 years ago
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I really need a quick answer! What is 8y + 12?
astra-53 [7]

Answer:

24

Step-by-step explanation:

To figure out what the value of y is, we must isolate the variable. To do this, we need to use the division property of equality which says that when you divide on one side of the equal sign, you must also divide on the other side.

8y/8 = y

12/8 = 1.5

This tells us the value of y, so next we have to apply this into the problem

8(1.5) = 12

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24 is your answer

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3 years ago
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What is the repeating digit<br> in the decimal equivalent of 4 over 9
lukranit [14]
4 is the repeating digit 
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3 years ago
Please I BEG you to help...
g100num [7]
Answer:

36x^8

Explanation:

Use the rules of exponents
6 0
3 years ago
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Findf '(3), where f(t) = u(t) · v(t), u(3) =1, 2, −2, u'(3) =8, 1, 4,andv(t) =t, t2, t3.
Reika [66]

Answer:

f'(3)=100

Step-by-step explanation:

Given:

f(t)=u(t)\cdot v(t)\\u(3)=\left ( 1,2,-2 \right )\\u'\left ( 3 \right )=\left ( 8,1,4 \right )\\v(t)=\left ( t,t^{2},t^{3} \right )

To find: f'(3)

Solution:

v(t)=\left ( t,t^{2},t^{3} \right )

At t=3;

v(3)=(3,3^{2},3^{3} )=(3,9,27)

Differentiate with respect to t

v'(t)=\left ( 1,2t,3t^{2} \right )

At t=3;

v'(3)=\left ( 1,2(3),3(3)^{2} \right )=\left ( 1,6,27 \right )

Using product rule, differentiate f(t)=u(t)\cdot v(t) with respect to t

f'(t)=u'(t)\cdot v(t)+u(t)\cdot v'(t)

At t=3;

f'(3)=u'(3)\cdot v(3)+u(3)\cdot v'(3)\\=\left ( 8,1,4 \right )\cdot \left ( 3,9,27 \right )+\left ( 1,2,-2 \right )\cdot \left ( 1,6,27 \right )\\=24+9+108+1+12-54\\=100

7 0
4 years ago
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