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joja [24]
3 years ago
11

The length and width of a rectangle are doubled. Write a formula for the new area. How is the area changed?​

Mathematics
1 answer:
Vaselesa [24]3 years ago
5 0

Answer:

2l + 2w = A

Step-by-step explanation:

l = length

w = width

A = Area

The area is doubled.

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Find the 9th term of the geometric sequence 5, -25, 125, ...
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  1,953,125

Step-by-step explanation:

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7 0
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Find the measure of Q, the smallest angle in the triangle whose sides have lengths 4-5, and 6. Round the measure to the nearest
kakasveta [241]

<u>Given</u>:

Given that PQR is a triangle.

The measures of the sides of the triangle are 4,5 and 6.

We need to determine the measure of ∠Q.

<u>Measure of ∠Q:</u>

The measure of ∠Q can be determined using the law of cosines formula.

Thus, we have;

\cos (Q)=\frac{p^{2}+r^{2}-q^{2}}{2 p r}

Substituting p = 6, q = 4, r = 5, we get;

\cos (Q)=\frac{6^{2}+5^{2}-4^{2}}{2 (6)(5)}

Simplifying, we get;

\cos (Q)=\frac{36+25-16}{2 (30)}

\cos (Q)=\frac{45}{60}

Dividing, we get;

\cos (Q)=0.75

      Q=cos^{-1}(0.75)

      Q=41^{\circ}

Thus, the measure of ∠Q is 41°

Hence, Option b is the correct answer.

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3 years ago
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