Math work pls help :)

8. The larger of two numbers is 8 more than twice the smaller. The sum of the

schepotkina [342]

Answer:

Step-by-step explanation:

Givens

smaller number = x

Larger number = 2x + 8

Sum = 35

Equation

x + 2x + 8 = 35

Solution

3x + 8 = 35

3x = 35 - 8

3x = 27

x = 9

The smaller number = 9

The larger number = 2*9 + 8 = 26

My answers aren't in the list. Are you sure the numbers in the list are correct?

6 0

3 years ago

Need help! Plzz help asap

finlep [7]

X=9 which makes HI 2 units

8 0

4 years ago

If X denotes the number of heads in n tosses of a coin, what is the standard deviation of the random variable X? Does this stand

vfiekz [6]

Answer:

$\sigma=\sqrt{np(1-p)}=\sqrt{n*0.5(1-0.5)}=\frac{\sqrt{n}}{2}$

As we can see the deviation is proportional to the value of n and if n increase then the deviation increases too. So then the deviation would be larger when n gets larger.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Solution to the problem

We can define the following random variable X ="Number of heads in n tosses of a coin".

We assume that the coin is fair and then $P(H)= 0.5$ for any trial so then we can model X with the following distribution:

$X \sim Bin (n, p=0.5)$

For this distribution the mean and variance are given by:

$E(X)=np=n*0.5=\frac{n}{2}$

$Var(X)= np(1-p) = n*0.5*(1-0.5) = 0.25 n = \frac{n}{4}$

And the deviation would be just the square root of the variance and we got:

$\sigma=\sqrt{np(1-p)}=\sqrt{n*0.5(1-0.5)}=\frac{\sqrt{n}}{2}$

Does this standard deviation get larger or smaller when n gets larger?

As we can see the deviation is proportional to the value of n and if n increase then the deviation increases too. So then the deviation would be larger when n gets larger.

3 0

3 years ago

6.02 is what percent of 67.5?

liraira [26]

I hope this helps you

6,02 %?= 67,5

602.?= 67,5

?= 67,5÷602

?=0,112

7 0

4 years ago

Christina Stratton invested $8,000 in a certificate of deposit for 4 years. The certificate earns interest at an annual rate of

galben [10]

Answer:

6.13%

Step-by-step explanation:

We are given an investment of $8000 deposited for 4 years. We have to find the effective annual yield for which we will need the interest rate and the compounding period.

Annual interest rate compunded quarterly, r = 6% = 0.06

Compounding period is quarterly, n = 4

Annual EffectiveYield = $(1+\frac{r}{n})^{n}-1\\=(1+\frac{0.06 }{4})^{4}-1$

= 0.0613

The annual effective yield is 6.13%

6 0

3 years ago

Math work pls help :)​

Math work pls help :)