Find the length of the hypotenuse

Please help me with those question please help with out number 1

alina1380 [7]

Answer:

1) For each value of x, a value of y is increased by 5.

x = 0, y = 5

x = 1, y = 10

x = 2, y = 15

x = 3, y = 20

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2) For each two values of x, a value of y is increased by 10.

x = 0, y = -2

x = 2, y = 8

x = 4, y = 18

x = 6, y = 28

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3)

x = 0, y = 1

x = 1, y = $\frac{7}{5}$

x = 5, y = 3

x = 10, y = 5

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4)

x = 0, y = 2

x = 1, y = 17

x = 2, y = 32

x = 5, y = 77

Step-by-step explanation:

This is as easy as replacing x for the actual value show on the table.

1)

$y=5x+5$

When x = 0, y = ?

$y=5(0)+5\\y=0+5\\y=5$

When x = 1, y = ?

$y=5(1)+5\\y=5+5\\y=10$

When x = 2, y = ?

$y=5(2)+5\\y=10+5\\y=15$

When x = 3, y = ?

$y=5(3)+5\\y=15+5\\y=20$

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2)

$y=5x-2$

When x = 0, y = ?

$y=5(0)-2\\y=0-2\\y=-2$

When x = 2, y = ?

$y=5(2)-2\\y=10-2\\y=8$

When x = 4, y = ?

$y=5(4)-2\\y=20-2\\y=18$

When x = 6, y = ?

$y=5(6)-2\\y=30-2\\y=28$

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3)

$y=\frac{2}{5}x +1$

When x = 0, y = ?

$y=\frac{2}{5}(0) +1$

$y=0 +1\\y=1$

When x = 1, y = ?

$y=\frac{2}{5}(1) +1\\y=\frac{2}{5} +1$

$y=\frac{2}{5}+1(\frac{5}{5})\\ y=\frac{2}{5}+\frac{5}{5} \\y=\frac{7}{5}$

When x = 5, y = ?

$y=\frac{2}{5}(5) +1\\y=2+1\\y=3$

When x = 10, y = ?

$y=\frac{2}{5}(10) +1\\y=2(2) +1\\y=4+1\\y=5$

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4)

$y=15x+2$

When x = 0, y = ?

$y=15(0)+2\\y=0+2\\y=2$

When x = 1, y = ?

$y=15(1)+2\\y=15+2\\y=17$

When x = 2, y = ?

$y=15(2)+2\\y=30+2\\y=32$

When x = 5, y = ?

$y=15(5)+2\\y=75+2\\y=77$

4 0

3 years ago

Read 2 more answers

PLEASE ANSWERRRRRRRR

hram777 [196]

Answer:

its the steepness of two numbers on a graph - measures the steepness of the line. (what a slope is)

y=40x+10

Step-by-step explanation:

y=mx+b

6 0

4 years ago

Help Number three please!!!

Lubov Fominskaja [6]

Step-by-step explanation:

108-ambulance

100- police

1098-child laber

5 0

3 years ago

Tickets to a concert cost $2 for children, $3 for teenagers and $5 for adults. When 570 people attended the concert, the total t

-Dominant- [34]

Let

x--------> the number of children

y------> the number of teenagers

z------> the number of adults

we know that

$2x+3y+5z=1,950$ ------> equation A

$x+y+z=570$ -----> equation B

$y=\frac{3}{4}x$

$x=\frac{4}{3}y$ -------> equation C

Substitute equation C in equation A and equation B

$2[\frac{4}{3}y]+3y+5z=1,950$

$\frac{17}{3}y+5z=1,950$ --------> equation D

$[\frac{4}{3}y]+y+z=570$

$\frac{7}{3}y+z=570$ --------> equation E

Multiply equation E by $-5$

$-\frac{35}{3}y-5z=-2,850$ --------> equation F

Adds equation D and equation F

$\frac{17}{3}y+5z=1,950\\\\-\frac{35}{3}y-5z=-2,850\\\\---------\\\\-\frac{18}{3}y=-900\\\\y=3*900/18\\\\y=150\ teenagers$

therefore

<u>the answer is the option</u>

$150\ teenagers$

4 0

3 years ago

Read 2 more answers

Graph the linear equation y=2.

MissTica

Answer:

Here is a picture of how you will graph this equation

Step-by-step explanation:

Hope this Helped

3 0

3 years ago

Read 2 more answers