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2 years ago

Please help w steps! asap

Mathematics

1 answer:

SSSSS [86.1K]2 years ago

8 0

Answer:

(4,6)

Step-by-step explanation:

The midpoint=( $\frac{5+3}{2} ,\frac{11+1}{2} )$

=(4,6)

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If u(x) = x^5 - x^4 + x^2 and v (x) = -x^2 which expression is equivalent to ( u/ v) (x)

yawa3891 [41]

Answer:

$(u/v)(x)=-x^{3}+x^{2}-1$

Step-by-step explanation:

You have the following functions:

$u(x)=x^{5}-x^{4}+x^{2}\\v(x)=-x^{2}$

Therefore $(u/v)(x)$ indicates that you must divide both functions, as you can see below:

$(u/v)(x)=\frac{x^{5}-x^{4}+x^{2}}{-x^{2}}$

Simplify it. Therefore, you obtain:

$(u/v)(x)=\frac{x^{5}-x^{4}+x^{2}}{-x^{2}}\\\\(u/v)(x)=-x^{3}+x^{2}-1$

3 0

2 years ago

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Please help again, sorry for asking…

prohojiy [21]

Answer:

BC=6x+4= 6x4+4 = 28 is the correct answer

AB+BC=AC

4x+8+6x+4=52

10x+12=52

10x=40

X=4

4 0

2 years ago

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Problem 4 Solve x^2-8x=5

ra1l [238]

Answer:C

Step-by-step explanation:

x=4+√21,4−√21

Decimal Form:

8.58257569

0.58257569

7 0

3 years ago

Khan khan khan khan

Ber [7]

Answer:

Step-by-step explanation:

it says motor cycles combined with garbage so add both of them then subtract that from the bull dosers

motor =18

garbage=4

18+4=22

bulldosers=11

22-11= 11 more

5 0

2 years ago

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I NEED HELP!! please show all work

PtichkaEL [24]

Take the logarithm of both sides. The base of the logarithm doesn't matter.

$4^{5x} = 3^{x-2}$

$\implies \log 4^{5x} = \log 3^{x-2}$

Drop the exponents:

$\implies 5x \log 4 = (x-2) \log 3$

Expand the right side:

$\implies 5x \log 4 = x \log 3 - 2 \log 3$

Move the terms containing x to the left side and factor out x :

$\implies 5x \log 4 - x \log 3 = - 2 \log 3$

$\implies x (5 \log 4 - \log 3) = - 2 \log 3$

Solve for x by dividing boths ides by 5 log(4) - log(3) :

$\implies \boxed{x = -\dfrac{ 2 \log 3 }{ 5 \log 4 - \log 3 }}$

You can stop there, or continue simplifying the solution by using properties of logarithms:

$\implies x = -\dfrac{ \log 3^2 }{ \log 4^5 - \log 3 }$

$\implies x = -\dfrac{ \log 9 }{ \log 1024 - \log 3 }$

$\implies \boxed{x = -\dfrac{ \log 9 }{ \log \frac{1024}3 }}$

You can condense the solution further using the change-of-base identity,

$\implies \boxed{x = -\log_{\frac{1024}3}9}$

5 0

2 years ago