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grin007 [14]
3 years ago
9

Let a[0 . . . n] be an array of n + 1 natural numbers not exceeding n. let k < n be an integer such that the values of any tw

o successive entries of a differ at most by k, i.e., |a[j] − a[j + 1]| ≤ k for all j ∈ {0, . . . , n − 1}. 1. prove that there exist an index j such that |a[j] − j| ≤ (k + 1)/2. 2. given the number k, find an o(log n) divide and conquer algorithm that finds such an index.
Mathematics
1 answer:
12345 [234]3 years ago
6 0

Answer:

i really have no clue but if i put this i get points so good luck on your test

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Find m&lt;v 36x-1 =29x+1​
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Answer:

M<36×-=36=29×+1=29.....

5 0
4 years ago
19810 rounded to the nearest hundred
Cloud [144]
19,810 rounded to the nearest hundred is 19,800.
8 is in the hundreds place, and the number 1 is in front of it.
 
Numbers 1-4 in front of the number make the number stay the same.

Numbers 5-9 in front of the number make the numbers round up one number.
3 0
3 years ago
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Do the ratios 10/8 and 16/20 form a proportion<br><br> Yes or no?
ziro4ka [17]

Answer:

No. Reduce 10/8 by dividing by 2. 10/8= 5, 8/2= 4. 10/8= 5/4. Reduce 16/20 by dividing by 4. 16/4= 4 , 20/4= 5. 16/20= 4/5.

6 0
3 years ago
If f(x) = 6x-11, what is f(-6)?​
In-s [12.5K]

If f(x) = (6x-11), then f(-6) = -47.

We are provided in the question statement with a function "f(x)" whose output is a polynomial of 1 variable and degree 1.

To obtain the value of f(-6) from the output polynomial of the function f(x), we will simply need to substitute (-6) as the value of x in the polynomial and calculate the final value.

So,

f(-6)=[(6*(-6))-11]\\or, f(-6)=(-36-11)\\or, f(-6)=-(36+11)\\or, f(-6) =-47

Hence, f(-6) = -47.

  • Polynomial: In mathematics, an expression of more than two algebraic terms, especially the sum of several terms that contain the same variable(s) of different powers and individual, distinct co-efficients.
  • Function: In Mathematics, a function is an operator which on taking input, provides a certain output.

To learn more about Polynomials and Functions, click on the link below.

brainly.com/question/26910958

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5 0
2 years ago
Số hạng đầu và số hạng thứ 2 của một cấp số nhân lần lượt là x+2 và x^2 -4 số hạng thứ 3 của cấp số nhân này là
GenaCL600 [577]

Answer:

x³-2x²-4x+8

Step-by-step explanation:

a1=x+2

a2=x²-4⇒q=a2/a1=x-2

⇒a3=q.a2=(x-2).(x²-4)=x³-2x²-4x+8

3 0
3 years ago
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