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3 years ago

Some one help me!,!!,!,!!!!!

Mathematics

1 answer:

ella [17]3 years ago

6 0

Answer:

See below in bold.

Step-by-step explanation:

The angle below and to the right of 30 degrees = 90-30 = 60 degrees,.

< EAC + 5x + 6x = 180

But m < EAC = the angle found in first line so its 60 degrees.

S0 3x + 5x + 60 = 180

8x = 120

x = 15

So m < CAB = 75 degrees and m < BAH = 45 degrees.

Finally the m < on top left = 90 degrees.

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Mike is 7.5 miles ahead of julia running at 5.5 miles per hour and julia is running at the speed of 6 miles per hour.How long do

GrogVix [38]

Answer:

15 hours.

Step-by-step explanation:

Suppose the time taken to catch Mike is t hours and the distance ran by Mike is x miles then

5.5 = x/ t (Mike) --- ...(1)

6 = (x +7.5 )/ t (Julia ).......(2)

From equation (1):

x = 5.5t ..............(3).

From equation (2):

x + 7.5 = 6t

x = 6t - 7.5............(4).

Eliminating x from equations 3 and 4:

6t - 7.5 = 5.5t

0.5t = 7.5

t = 15 hours.

5 0

3 years ago

PLS ANSWER ASAP 30 POINTS!!! CHECK PHOTO! WILL MARK BRAINLIEST TO WHO ANSWERS

Sveta_85 [38]

I'll do Problem 8 to get you started

a = 4 and c = 7 are the two given sides

Use these values in the pythagorean theorem to find side b

$a^2 + b^2 = c^2\\\\4^2 + b^2 = 7^2\\\\16 + b^2 = 49\\\\b^2 = 49 - 16\\\\b^2 = 33\\\\b = \sqrt{33}\\\\$

With respect to reference angle A, we have:

opposite side = a = 4
adjacent side = b = $\sqrt{33}$
hypotenuse = c = 7

Now let's compute the 6 trig ratios for the angle A.

We'll start with the sine ratio which is opposite over hypotenuse.

$\sin(\text{angle}) = \frac{\text{opposite}}{\text{hypotenuse}}\\\\\sin(A) = \frac{a}{c}\\\\\sin(A) = \frac{4}{7}\\\\$

Then cosine which is adjacent over hypotenuse

$\cos(\text{angle}) = \frac{\text{adjacent}}{\text{hypotenuse}}\\\\\cos(A) = \frac{b}{c}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\$

Tangent is the ratio of opposite over adjacent

$\tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}}\\\\\tan(A) = \frac{a}{b}\\\\\tan(A) = \frac{4}{\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{\sqrt{33}*\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{(\sqrt{33})^2}\\\\\tan(A) = \frac{4\sqrt{33}}{33}\\\\$

Rationalizing the denominator may be optional, so I would ask your teacher for clarification.

So far we've taken care of 3 trig functions. The remaining 3 are reciprocals of the ones mentioned so far.

cosecant, abbreviated as csc, is the reciprocal of sine
secant, abbreviated as sec, is the reciprocal of cosine
cotangent, abbreviated as cot, is the reciprocal of tangent

So we'll flip the fraction of each like so:

$\csc(\text{angle}) = \frac{\text{hypotenuse}}{\text{opposite}} \ \text{ ... reciprocal of sine}\\\\\csc(A) = \frac{c}{a}\\\\\csc(A) = \frac{7}{4}\\\\\sec(\text{angle}) = \frac{\text{hypotenuse}}{\text{adjacent}} \ \text{ ... reciprocal of cosine}\\\\\sec(A) = \frac{c}{b}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(\text{angle}) = \frac{\text{adjacent}}{\text{opposite}} \ \text{ ... reciprocal of tangent}\\\\\cot(A) = \frac{b}{a}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\$

------------------------------------------------------

Summary:

The missing side is $b = \sqrt{33}$

The 6 trig functions have these results

$\sin(A) = \frac{4}{7}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\\tan(A) = \frac{4}{\sqrt{33}} = \frac{4\sqrt{33}}{33}\\\\\csc(A) = \frac{7}{4}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\$

Rationalizing the denominator may be optional, but I would ask your teacher to be sure.

7 0

2 years ago

HELP ASAP PLZPLZPLZPLPLZPZLPLZPLZPZLPZLPLZPLZPZLZP

DedPeter [7]

Your answer should be b. :)

Have a awesome day!!!!

8 0

4 years ago

Eight eagle stamps and two raccoon stamps cost $2.80. Three eagle stamps and four raccoon stamps cost $2.35. Find the cost of ea

nikklg [1K]

Answer:

Cost of each eagle stamp = $0.25

Cost of each racoon stamp = $0.4

Step-by-step explanation:

Given:

Cost of 8 eagle stamp and 2 racoon stamp = $2.80

Cost of 3 eagle stamp and 4 racoon stamp = $2.35

Find:

Cost of each stamp

Computation:

Assume;

Cost of each eagle stamp = e

Cost of each racoon stamp = r

So,

8e + 2r = 2.80........... Eq 1

3e + 4r = 2.35 ........... Eq 2

Eq 1 x 2

16e + 4r = 5.6 .........Eq3

Eq 3 - Eq 2

13e = 3.25

e = 0.25

Cost of each eagle stamp = $0.25

8e + 2r = 2.80

8(0.25) + 2r = 2.80

2 + 2r = 2.80

r = 0.4

Cost of each racoon stamp = $0.4

6 0

3 years ago

Write two facts that you learned about continuity .

Mashutka [201]

Answer:

As I learned

It makes us success and helps to learn the habit of being patience

It is needed to become experienced and matured,so that while doing the same work again we won't make mistake

8 0

3 years ago