Answer:
<h2>Kelly is wrong, with this congruent parts, we can conclude that triangles are congruent.</h2>
Step-by-step explanation:
To demonstrate congruent triangles, we need to use the proper postulates. There are at least 5 postulates we can use.
- Angle-Angle-Side Theorem (AAS theorem).
- Hypotenuse-Leg Theorem (HL theorem).
- Side-Side-Side Postulate (SSS postulate).
- Angle-Side-Angle Postulate (ASA postulate).
- Side-Angle-Side Postulate (SAS postulate).
In this case, Kelly SAS postulate, because the corresponding sides-angles-sides are congruent, i.e., KL ≅ MN and LM ≅ KN, also, all corresponding angles are congruent.
So, as you can see, only using SAS postulate, the congruency can be demonstrated. (Refer to the image attached to see an example of SAS postulate)
Okay, to find length CE, your going to know the value of <em>x</em>. Length BC + CE = BD + DE.
3x+47+x+26=27+x+10
Simplify the equation to get
4x+73=37+x
you can choose one of four ways to continue, but I will choose to subtract x
3x+73=37
Subtract 73 from both sides of the equal sign
3x=-36
divide by 3 on both sides of the equal sign to get the value of x
x=-12
Now, plug in -12 for x in length CE to get -12+26=14
Answer:
x = -2
Step-by-step explanation:
x^a × x^b = x^(a+b)
Similarly,
(5/3)^(-5) × (5/3)^(-11) = (5/3)^(-5-11)
= (5/3)^(-16)
-16 = 8x
x = -2
The angle measures tell you the triangles are similar, so corresponding sides will have the same ratio.
GX/BX = UH/NH
GX = BX·UH/NH
GX = 7·18/(3√11)
GX = (42/11)√11
GB/BX = UN/NH
GB = BX·UN/NH
GB = 7·15/(3√11)
GB = (35/11)√11