76.88 I just typed it in on a calculator.
Answer:
19ft
Step-by-step explanation:
Given the height of a ball above the ground after x seconds given by the quadratic function y = -16x2 + 32x + 3, we can find the maximum height reached by the ball since we are not told what to look for.
The velocity of the ball is zero at maximum height and it is expressed as:
V(x) = dy/dx
V(x) = -32x+32
Since v(x) = 0
0 = -32x+32
32x = 32
x = 32/32
x = 1s
Get the height y
Recall that y = -16x² + 32x + 3.
Substitute x = 1
y = -16(1)²+32(1)+3
y = -16+32+3
y = -16+35
y = 19ft
Hence the maximum height reached by the ball is 19ft
Answer:
Interior angles im pretty sure
d^2+35+109=180
d=6
HOPE THIS HELPS
-Todo <3
Step-by-step explanation:
d^2+35+109=180
144+d^2=180
-144 -144
36=d^2
d=6
Answer:
3/41; 1/6 40/97
Step-by-step explanation:
Answer:
X would have to equal more than 5
Step-by-step explanation:
When the open part of the thingy, the <, is facing the 3x, it means that its bigger than the 15, and 3*5 is 15, x has to equal more than 5
