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tester [92]
3 years ago
14

Martha paid $42.40 for her sister’s birthday present. This included 6% sales tax. What was the cost of the gift before tax? A. $

44.94 B. $40.00 C. $25.44 D. $2.40
Mathematics
1 answer:
kifflom [539]3 years ago
4 0
I think the answer is 40.00

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A father is eight times as old as his son . In 10 years , he will be three times as old as his son . The age of son is
vodka [1.7K]

Answer:

The son is 4years old

Step-by-step explanation:

Let the son's age=x

the father's age=8x

IN 10YEARS,

Son's age=x+10

father's age=8x+10

Equate them

8x+10=3(x+10)

8x+10=3x+30

5x=20

x=4

6 0
3 years ago
Which is the solution of the equation 1/4 ( 3x - 1 ) = 2x -2/3
Sever21 [200]

Answer:

x = 1/3 = 0.333

Step-by-step explanation:

Step  1  :

           2

Simplify   —

           3

Equation at the end of step  1  :

  1                       2

 (— • (3x - 1)) -  (2x -  —)  = 0

  4                       3

Step  2  :

Rewriting the whole as an Equivalent Fraction :

2.1   Subtracting a fraction from a whole

Rewrite the whole as a fraction using  3  as the denominator :

          2x     2x • 3

    2x =  ——  =  ——————

          1        3  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

2x • 3 - (2)     6x - 2

————————————  =  ——————

     3             3  

Equation at the end of step  2  :

  1                (6x - 2)

 (— • (3x - 1)) -  ————————  = 0

  4                   3    

Step  3  :

           1

Simplify   —

           4

Equation at the end of step  3  :

  1                (6x - 2)

 (— • (3x - 1)) -  ————————  = 0

  4                   3    

Step  4  :

Equation at the end of step  4  :

 (3x - 1)    (6x - 2)

 ———————— -  ————————  = 0

    4           3    

Step  5  :

Step  6  :

Pulling out like terms :

6.1     Pull out like factors :

  6x - 2  =   2 • (3x - 1)

Calculating the Least Common Multiple :

6.2    Find the Least Common Multiple

     The left denominator is :       4

     The right denominator is :       3

       Number of times each prime factor

       appears in the factorization of:

Prime

Factor   Left

Denominator   Right

Denominator   L.C.M = Max

{Left,Right}

2 2 0 2

3 0 1 1

Product of all

Prime Factors  4 3 12

     Least Common Multiple:

     12

Calculating Multipliers :

6.3    Calculate multipliers for the two fraction

   Denote the Least Common Multiple by  L.C.M

   Denote the Left Multiplier by  Left_M

   Denote the Right Multiplier by  Right_M

   Denote the Left Deniminator by  L_Deno

   Denote the Right Multiplier by  R_Deno

  Left_M = L.C.M / L_Deno = 3

  Right_M = L.C.M / R_Deno = 4

Making Equivalent Fractions :

6.4      Rewrite the two fractions into equivalent fraction

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      (3x-1) • 3

  ——————————————————  =   ——————————

        L.C.M                 12    

  R. Mult. • R. Num.      2 • (3x-1) • 4

  ——————————————————  =   ——————————————

        L.C.M                   12      

Adding fractions that have a common denominator :

6.5       Adding up the two equivalent fractions

(3x-1) • 3 - (2 • (3x-1) • 4)     5 - 15x

—————————————————————————————  =  ———————

             12                     12  

Step  7  :

Pulling out like terms :

7.1     Pull out like factors :

  5 - 15x  =   -5 • (3x - 1)

Equation at the end of step  7  :

 -5 • (3x - 1)

 —————————————  = 0

      12      

Step  8  :

When a fraction equals zero :

8.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 -5•(3x-1)

 ————————— • 12 = 0 • 12

    12    

Now, on the left hand side, the  12  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  -5  •  (3x-1)  = 0

Equations which are never true :

8.2      Solve :    -5   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

8.3      Solve  :    3x-1 = 0

Add  1  to both sides of the equation :

                     3x = 1

Divide both sides of the equation by 3:

                    x = 1/3 = 0.333

One solution was found :

                  x = 1/3 = 0.333

Processing ends successfully

plz mark me as brainliest :)

4 0
3 years ago
A rectangle is 5.1 cm wide and each diagonal is 9.3 cm long. What is the measure of the angle between a diagonal and the shorter
Anastasy [175]

Answer:

56.7°

Step-by-step explanation:

A rectangle is 5.1 cm wide and each diagonal is 9.3 cm long. What is the measure of the angle between a diagonal and the shorter side of the rectangle to the nearest tenth of a degree?

We solve this question using the Trigonometric function of Sine

From the question, we are told that:

A rectangle is 5.1 cm wide

and each diagonal is 9.3 cm long.

Since we have a diagonal, this means the shape is transformed to a triangle.

The width of the rectangle = Adjacent side of a triangle = 5.1cm

The diagonal of the rectangle = Hypotenuse = 9.3cm

Hence,

cosθ = Adjacent/Hypotenuse

cosθ = 5.1/9.3

cosθ = 0.5483870968

θ = arccos(0.5483870968)

θ = 56.743568714°

Approximately = 56.7°

The measure of the angle is 56.7°

3 0
3 years ago
Isabel is riding on a bike course that is 36 miles long. So far , she has ridden 9 miles of the course. What Percentage of the c
Margaret [11]
This is one fourth of the course, so 25%.
4 0
3 years ago
Read 2 more answers
I need help with this ASAP and can you explain so i can understand?!
Elanso [62]

Answer:

Adult tickets sold =  225

Student Tickets sold =  375

Step-by-step explanation:

Let:

Adult tickets sold = x

Student Tickets sold = y

Total tickets sold = 600

So, we can write: x+y = 600

Total money collected = 3037.50

Cost of 1 Adult ticket = $6.00

Cost of one Student ticket = $4.50

So, we can write: 6x+4.5y=3037.50

Now, we get a system of equations, that if solved we can find values of x and y

Let:

x+y = 600--eq(1)\\6x+4.5y=3037.50--eq(2)

We can solve using substitution method.

Finding value of x from eq(1) and putting it in eq(2)

We\:have\\x+y=600\\x=600-y

Put in eq(2)

6x+4.5y=3037.50\\6(600-y)+4.5y=3037.50\\3600-6y+4.5y=3037.50\\-1.5y=3037.50-3600\\-1.5y=-562.5\\y=\frac{-562.5}{-1.5}\\y=375

So, we get value of y = 375

Now put value of y in eq(1) to find value of x

x+y=600\\Put\:y=375\\x+375=600\\x=600-375\\x=225

So, we get value of x = 225

The Tickets sold will be:

Adult tickets sold = x = 225

Student Tickets sold = y = 375

3 0
3 years ago
Read 2 more answers
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