Answer:
f(2) = 16
or
y = 16
Step-by-step explanation:
Step 1: Write out function
y = 6x + 4
Step 2: Define variable for problem
<em>x</em> = 2
Step 3: Plug into function f(x)
f(2) = 6(2) + 4
f(2) = 12 + 4
f(2) = 16
Step 4: Change f(2) to y
y = 16
so leg A would be 60
leg B would be 85
using this we are able to determine the HYP to be 104.04
so sine = opp/HYP
leg A is the opp in this case
sin(theta) = 60/104.04
sin(theta) = 0.57670126874
when we round to the hundredths place we get 0.58
:dab:
Answer:
15
Step-by-step explanation:
thats the answer im not sure if u want me to explain it. But if you do need it to be explained look it up. Give brainliest please.
Answer:
(6^4 x 2^-9)
Step-by-step explanation:
The space between the two spheres will be the volume of the larger sphere minus the volume of the smaller sphere. Given that the volume of any sphere is:
V=(4πr^3)/3 The space between to sphere of different radius and positioned about the same center is:
S=(4πR^3)/3-(4πr^3)/3 I used S=volume of space, R=larger radius and r=smaller radius...
S=(4π/3)(R^3-r^3), we are told that R=5 and r=4 so
S=(4π/3)(5^3-4^3)
S=(4π/3)(125-64)
S=(4π/3)(61)
S=244π/61
S=4π cm^3
S≈12.57 cm^3 (to nearest hundredth of a ml)
