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4 years ago

Let f(x) = 3x2 - 6x + 2. Find f(2)

Mathematics

2 answers:

Akimi4 [234]4 years ago

8 0

F(2) will equal 37 then plug it in where x is

yanalaym [24]4 years ago

8 0

Answer:

f(2) = 2 .

Step-by-step explanation:

Given: f(x)=3x² - 6x + 2.

To find: f(2) .

Solution: We have given that f(x)=3x² - 6x + 2.

plugging the value of x =2

f(x)=3x² - 6x + 2

f(2)= 3(2)² - 6(2) + 2

f(2)= 3×4 -12 + 2

f(2) =12 -12 +2

so, f(2) = 2

Therefore, f(2) = 2 .

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The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E

nexus9112 [7]

Answer:

The projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

Step-by-step explanation:

Consider the provided projected rate.

$E'(t) = 12000(t + 9)^{\frac{-3}{2}}$

Integrate the above function.

$E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt$

$E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c$

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$2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c$

$2000=-\frac{24000}{3}+c$

$2000=-8000+c$

$c=10,000$

Therefore, $E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

Now we need to find $\lim_{t \to \infty} E(t)$

$\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

$\lim_{t \to \infty} E(t)=10,000$

Hence, the projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

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