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Burka [1]
2 years ago
7

*BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST**

Mathematics
1 answer:
aev [14]2 years ago
7 0

Step-by-step explanation:

These aren't a perfect square bec. 1 st and 3rd terms must be perfect square

A(X) = X^2+6X +13 be perfect square if 13 Changed to 9

= X ^2+6X +9

A(x)= 2X^2+8X +14 be perfect square

= 4X ^2+ 8X + 16

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