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Pavlova-9 [17]
2 years ago
7

Which phrase best describes the translation from the graph y = (x – 5)2 + 7 to the graph of y = (x + 1)2 – 2?

Mathematics
1 answer:
Andreas93 [3]2 years ago
8 0

The parent. function shifted up by 6 units to produce x + 1 and to the left by 9 units

<h3>What is translation?</h3>

This is a way of changing the position of an object on an xy-plane.

Given the parent function expressed as  y = (x – 5)^2 + 7

From the resulting image after translation, we can see that the parent. function shifted up by 6 units to produce x + 1 and to the left by 9 units

Learn more on translation here; brainly.com/question/12861087

#SPJ1

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Answer:

Step-by-step explanation:

The easiest way is to graph both functions and see where they intersect.  The intersection is where f(x) = g(x).

f(x) = -x² - 3x + 6

g(x) = 2x² + 5x + 3

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This is a 3 part 1 question each part on how to locate the plane and a small explanation report working out the recovery details
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Third leg.

The crew flies at a speed of 560 mi/h in direction N-20°-E.

The wind has a speed of 35 mi/h and a direction S-10°-E.

We then can draw this as:

We have to add the two vectors to find the actual speed and direction.

We will start by adding the x-coordinate (W-E axis):

\begin{gathered} x=560\cdot\sin (20\degree)+35\cdot\sin (10\degree) \\ x\approx560\cdot0.342+35\cdot0.174 \\ x\approx191.53+6.08 \\ x\approx197.61 \end{gathered}

and the y-coordinate (S-N axis) is:

\begin{gathered} y=560\cdot\cos (20\degree)-35\cdot\cos (10\degree) \\ y\approx560\cdot0.940-35\cdot0.985 \\ y\approx526.23-34.47 \\ y\approx491.76 \end{gathered}

Then, the actual speed vector is v3=(197.61, 491.76).

The starting location for the third leg is R2=(216.66, 167.67) [taken from the previous answer].

Then, we have to calculate the displacement in 20 minutes using the actual speed vector.

We can calculate the movement in each of the axis. For the x-axis:

\begin{gathered} R_{3x}=R_{2x}+v_{3x}\cdot t \\ R_{3x}=216.66+197.61\cdot\frac{1}{3} \\ R_{3x}=216.66+65.87 \\ R_{3x}=282.53 \end{gathered}

NOTE: 20 minutes represents 1/3 of an hour.

We can do the same with the y-coordinate:

\begin{gathered} R_{3y}=R_{2y}+v_{3y}\cdot t \\ R_{3y}=167.67+491.76\cdot\frac{1}{3} \\ R_{3y}=167.67+163.92 \\ R_{3y}=331.59 \end{gathered}

The final position is R3 = (282.53, 331.59).

To find the distance from the origin and direction, we transform the cartesian coordinates of R3 into polar coordinates:

The distance can be calculated as if it was a right triangle:

\begin{gathered} d^2=x^2+y^2_{} \\ d^2=282.53^2+331.59^2 \\ d^2=79823.20+109951.93 \\ d^2=189775.13 \\ d=\sqrt[]{189775.13} \\ d\approx435.63 \end{gathered}

The angle, from E to N, can be calculated as:

\begin{gathered} \tan (\alpha)=\frac{y}{x} \\ \tan (\alpha)=\frac{331.59}{282.53} \\ \tan (\alpha)\approx1.1736 \\ \alpha=\arctan (1.1736) \\ \alpha=49.56\degree \end{gathered}

If we want to express it from N to E, we substract the angle from 90°:

\beta=90\degree-\alpha=90-49.56=40.44\degree

Answer: the final location can be represented with the vector (282.53, 331.59).

1) The distance from the origin is 435.63 miles and

2) the direction is N-40°-E.

7 0
1 year ago
Can someone help me please
soldier1979 [14.2K]

Step-by-step explanation:

c >= 2

that means any value of c greater or equal to 2 is a valid solution. so, yes, 2 is a solution for this.

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that means any value of c smaller than 2 is a valid solution. so, no, 2 is not smaller than 2, so it is not a solution.

c < 3

that means any value of c smaller than 3 is a valid solution. so, yes, 2 is smaller than 3, so 2 is a solution.

3 < c

that means any value of c, for that 3 is smaller, is a valid solution. our in other words, any value for c larger than 3 is a valid solution. so, no, 2 is not larger than 3, so it is not a solution.

-8 < c

that means any value of c, for that -8 is smaller, is a valid solution. our in other words, any value for c larger than -8 is a valid solution. so, yes, 2 is larger than -8, so it is a solution.

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