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iren2701 [21]
2 years ago
8

What is 5(x + 6)+11 =25 3x​

Mathematics
1 answer:
Talja [164]2 years ago
4 0

Answer:

x=-\frac{16}{5}

Step-by-step explanation:

5(x+6)+11=25

Use the distributive property to multiply 5 by x+6.

5x+30+11=25

Add 30 and 11 to get 41.

5x+41=25

Subtract 41 from both sides.

5x=25−41

Subtract 41 from 25 to get −16.

5x=−16

Divide both sides by 5.

x=-16/5

Fraction -16/5 can be rewritten as -16/5 by extracting the negative sign.

x = -\frac{16}{5}

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A 1 newton force will stretch a spring 1 meter. The spring/mass system is damped by a force that is 8 times the instantaneous ve
sukhopar [10]

Answer:

Step-by-step explanation:

Given the mass is m =16kg, and 1N force will stretch the spring 1 m.

That is, F =1N,Z =1m. Now find the spring constant k:

F = kL = 1 = k(1) = k= 1N/m.

The damping force is 8times the instantaneous velocity, this means β = 8,

and the external force is f(t) = 0

Initially the object compressed 0.6m above equilibrium position,

with the downward velocity is 2m/s.

The differential equation for a spring mass system with

damping force and extemal force is: mx" + βxt + kx = f(t).

so, 16x"+ 8x' + x= 0, x(0} = -0.6, x'(0)= 2m/s.

Now solve the DE:

The auxilary equation for the homogeneous equation is 16x"+8x'+x=0

solving we get, 16r² + 8r + 1 = 0 => (4r + 1)² = 0 => r = - 1/4.

Then the general solution for the homogenous system is: x(t)=c_1e^{-t/4} +c_2te^{-t\4}.

Use the initial conditions x (0) = -0.6, x'(0) = 2m/s:

x(0)=c_1e^{0} +c_2(0)e^{0}=-0.6=c_1\\x'(t)=-\frac{1}{4}c_1e^{-t/4}+c_2e^{-t/4}-\frac{1}{4}c_2te^{-t/4}\\x'(0)=-\frac{1}{4}c_1e^0+c_2e^0-\frac{1}{4}c_2(0)e^0=2=-\frac{1}{4}(-0.6)+c_2=c_2=1.85.

Hence, x(t) =-0.6e^{-t/4}+1.85te^{-t/4}.

5 0
2 years ago
How many paychecks do you get a year if you're paid semimonthly?
hjlf
Semi --> twice
semimonthly --> occuring twice a month

Thus:
You are paid twice a month

12 months in a year

12 x 2 = 24 paychecks an year
6 0
2 years ago
HOw do you find what are the x intercepts of a graph
maw [93]
Wherever the line hits on the horizontal line on a graph.
5 0
3 years ago
Read 2 more answers
I WILL MARK BRAINLIEST IN 5 MINUTES!<br> solve this and explain
miskamm [114]

Answer:

no, it's not.

Step-by-step explanation:

300- 284 = 16

284 - 236 = 48

236 - 156 = 80

156 - 44 = 112

for every one the top line goes up, the bottom line changes too, but it's not at a constant rate. it's not constant, therefore it cannot be linear.

the rate of change formula (or slope formula, they're the same thing) is :

y2- y1/ x2 -x1 and to solve it you plug in the points. x is the same a t and y is h

284-300/ 1-0

-16 /1

-16 (this is the rate of change between the first two points)

236- 284/ 2-1

-48/ 1

-48 (rate of change between the second and third points)

since the rate of change isn't constant, it's not possible for it to be a linear relationship.

7 0
3 years ago
What is the total price of a $15 meal including 6% sales tax?
aev [14]
15×1.06
=15.9
therefor it is $15.90
4 0
3 years ago
Read 2 more answers
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