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olga_2 [115]
3 years ago
5

1 − 3 10 . Write the answer as a fraction

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
8 0

Answer:

7/10

Step-by-step explanation:

7 at the top, 10 at the bottom

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A central angle theta in a circle of radius 7 m is subtended by an arc of length 8 m. Find the measure of theta in degrees. (Rou
gogolik [260]

Answer: In degrees , The measure of \theta=65.5^{\circ}

In radians , the measure of  \theta =\dfrac{8}{7}\text{ radians}.

Step-by-step explanation:

We know that the formula for length of arc is given by :-

l=\theta r

, where \theta = Central angle subtended by arc.

r= radius of the circle.

As per given , we have

Radius of circle : r=7 m

Length of arc : l=  8 m

Substitute these values in the above formula , we get

8=\theta (7)\\\\\Rightarrow\ \theta =\dfrac{8}{7}\text{ radians}

Hence, the measure of \theta =\dfrac{8}{7}\text{ radians}.

To convert it into degrees we multiply it with \dfrac{180^{\circ}}{\pi}

The measure of \theta =\dfrac{8}{7}\times\dfrac{180^{\circ}}{\pi}

=(\dfrac{8\times180}{7\times3.14})^{\circ}=65.5141037307^{\circ}

\approx65.5^{\circ}

Hence, the measure of \theta=65.5^{\circ}

8 0
3 years ago
I feel like this is the same thing from my last question (about how to find arc and angle lengths) but it looks very different.
Gnesinka [82]

Yes it is the same except there are two arcs you need to find the length for in this one.

7 0
3 years ago
The sum of 5 consecutive integers is 265. What is the fifth number in this sequence ?
Yanka [14]
Hello,
Let's assume n,n+1,n+2,n+3,n+4 the 5 numbers

n+(n+1)+...+(n+4)=5n+10=265
5n=265-10
5n=255
n=51
The 5th number is 51+4=55

6 0
3 years ago
I need help. Thank you.
Oduvanchick [21]

Answer:

D

A=-5

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
the sum of the first n terms of a sequence is 20 - 10 / 2 ^ n - 1 find the sum of the first five terms​
Travka [436]

Answer:

S_5=\dfrac{170}{9}

Step-by-step explanation:

Given that,

The sum of first n term of a sequence isS_n=20-\dfrac{10}{2n-1}

We need to find the sum of the first 5 terms.

Put n = 5,

S_5=20-\dfrac{10}{2(5)-1}\\\\=20-\dfrac{10}{10-1}\\\\=20-\dfrac{10}{9}\\\\=\dfrac{170}{9}

So, the sum of first 5 terms is equal to \dfrac{170}{9}.

6 0
2 years ago
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