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enot [183]
3 years ago
15

PLEASE HELP!! i’ll make you a brainliest. i don’t want to fail.

Mathematics
1 answer:
Zinaida [17]3 years ago
8 0

Answer:

fisrt one is y=1/2x

second one is y=x+11

third one is y= x^3

fourth on is y= ^3 check mark x

Step-by-step explanation:

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Answer:

Sorry, don't know how to do this.

7 0
3 years ago
Please help me please
ioda
Use the pythagorean theorem:

a^2 + b^2 = c^2

plug in the given values:

0.7^2 + b^2 = 2.5^2

simplify:

0.49 + b^2 = 2.5^2

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3 years ago
The solutions to the inequality y s 2x - 4 are shaded on the
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3 0
3 years ago
PLEASE HELP WILL MARK BRAINLIEST
Sholpan [36]

Answer: Choice D

b greater-than 3 and StartFraction 2 over 15 EndFraction

In other words,

b > 3 & 2/15

or

b > 3\frac{2}{15}\\\\

========================================================

Explanation:

Let's convert the mixed number 2 & 3/5 into an improper fraction.

We'll use the rule

a & b/c = (a*c + b)/c

In this case, a = 2, b = 3, c = 5

So,

a & b/c = (a*c + b)/c

2 & 3/5 = (2*5 + 3)/5

2 & 3/5 = (10 + 3)/5

2 & 3/5 = 13/5

The inequality 2 \frac{3}{5} < b - \frac{8}{15}\\\\ is the same as \frac{13}{5} < b - \frac{8}{15}\\\\

---------------------

Let's multiply both sides by 15 to clear out the fractions

\frac{13}{5} < b - \frac{8}{15}\\\\15*\frac{13}{5} < 15*\left(b - \frac{8}{15}\right)\\\\39 < 15b-8\\\\

---------------------

Now isolate the variable b

39 < 15b-8\\\\15b-8 > 39\\\\15b > 39+8\\\\15b > 47\\\\b > \frac{47}{15}\\\\b > \frac{45+2}{15}\\\\b > \frac{45}{15}+\frac{2}{15}\\\\b > 3+\frac{2}{15}\\\\b > 3\frac{2}{15}\\\\

Side note: Another way to go from 47/15 to 3 & 2/15 is to notice how

47/15 = 3 remainder 2

The 3 is the whole part while 2 helps form the fractional part. The denominator stays at 15 the whole time.

7 0
3 years ago
Factor -4 out of -12r + 20.
Wewaii [24]

Answer:-12r+20=-4(3r-5)

Step-by-step explanation:

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3 years ago
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